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Softa [21]
3 years ago
9

Given the functions f(x) = 3x and g(x) = x² + 1, find [(gºf)(x)]- [(fºg)(x)].

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

6x^2 - 2

Step-by-step explanation:

plug in f(x) into the g(x) formula given

g(f(x)) = (3x)^2 + 1

simplify

= 9x^2+2

plug in g(x) into the f(x) formula given

f(g(x)) = 3(x^2+1)

distribute

= 3x^2 +3

set g(f(x)) - f(g(x))

(9x^2+2) - (3x^2+3)

carry the negative

9x^2+2-3x^2-3

simplify by combining like terms

6x^2-2

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A survey is being conducted in a county where 62% of the voters are Democrats and 38% are Republican. (a) What is the probabilit
Inessa05 [86]

Answer:

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either the voter is a Democrat, or he is not. The probability of the voter being a Democrat is independent of other voters. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

62% of the voters are Democrats

This means that p = 0.62

(a) What is the probability that two independently surveyed voters would both be Democrats?

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.62)^{2}.(0.38)^{0} = 0.3844

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

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2 years ago
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Step-by-step explanation:

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3 years ago
Write the expression 44(4–7)(4) using a single exponent.
Ghella [55]
<h3>The given expression as single exponent is:</h3>

4^4 \times 4^{-7} \times 4 = 4^{-2}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

4^4 \times 4^{-7} \times 4

In exponents,

When the base is same, exponents can be added

Which means,

a^m \times a^n = a^{m+n}

Therefore,

4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}

Thus the given expression as single exponent is:

4^4 \times 4^{-7} \times 4 = 4^{-2}

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