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arlik [135]
3 years ago
14

Cross multiply to determine whether the fractions are equivalent.

Mathematics
1 answer:
tester [92]3 years ago
7 0

Answer:

E

Step-by-step explanation:

28=28

14*2=28

4*28

they are both equal

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An ostrich that is 63 inches tall is 17 inches taller than 2 times the height of a kiwi.
DerKrebs [107]

Answer:

The kiwi is 23 inches tall.

Step-by-step explanation:

63= 2k + 17

46= 2k

k= 23 inches tall

8 0
3 years ago
Help me solve this problem
eduard

Answer:

b.   (-1, 5)

Step-by-step explanation:

Since the first equation is already solved for y, we can use substitution.

Substitute y in the second equation with 3x + 8.

5x + 2y = 5

5x + 2(3x + 8) = 5

5x + 6x + 16 = 5

11x = -11

x = -11/11

x = -1

Now substitute x in the first original equation by -1 and solve for y.

y = 3x + 8

y = 3(-1) + 8

y = -3 + 8

y = 5

Answer: (-1, 5)

8 0
1 year ago
Read 2 more answers
Prime factorization practice All factors
Alenkasestr [34]
1. -1•5•5 or also -1•5²
2. -1•7•7 -1•7²
3. -1•7
4. -1•13
5. -1•2•2•2•3 -1•2³•3
6.-1•2•2•2•2•3 -1•2^4•3
7. -1•2•2•2•3•7 -1•2³•3•7
Both factorization are correct it just depends on your teacher how she/he wants you to write it.
5 0
3 years ago
A regular heptagon has a side length of 13.9 and an apothem of 14.4. Find the area of the regular heptagon. Round your answer to
ivann1987 [24]

Answer: 701

Step-by-step explanation:

A heptagon has 7 sides, therfore a regular heptagon will have 7 equal sides

n = 7 (number of sides)

s = 13.9 (length of each sides of the heptagon)

r = 14.4 (The apothem)

The area of the regular heptagon can be calculated by:

Area = ½ n × s × r

Area = ½ × 7 × 13.9 × 14.4

Area = 700.56 square units

To the nearest whole number, will be:

Area = 701 square units

4 0
3 years ago
Need help finding the area of the shaded region
abruzzese [7]

Check the picture below, the assumption being that the 6ft line is perpendicular to the 18ft line and thus making a right-triangle.

now, if we just get the whole area of the containing parallelogram and then <u>get the area of the triangle and subtract it from that of the parallelogram's,</u> what's leftover is the area we didn't subtract, the shadead area.

\stackrel{ \textit{\LARGE Areas}}{\stackrel{parallelogram}{(18)(10)}~~ - ~~\stackrel{triangle}{\cfrac{1}{2}(18)(6)}}\implies 180~~ - ~~54\implies 126

7 0
2 years ago
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