Use the following frequency distribution to determine the midpoint of the second class.
1 answer:
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<h2>Answer:</h2>
The graph on the top left.
<h2>Step-by-step explanation:</h2>f(x) =
That means that when x = 0...
f(0) =
f(0) = -1 - 3
f(0) = -4
So, the function will have a point at (0, -4). We can eliminate the two graphs on the right.
When x = 1...
f(1) =
f(1) = -4 - 3
f(1) = -7
So, the function will have a point at (1, -7). That corresponds to the graph on the top left.
<h2>Hope this helps! </h2>