If the ball is dropped from 550ft height then what else could be the right answer.. I would go with 550ft
Answer:
f(x) = 0.01 × 2^(x+1)
Step-by-step explanation:
0.02 = 0.01 × 2¹
0.04 = 0.01 × 2²
0.08 = 0.01 × 2³
0.16 = 0.01 × 2⁴
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
3.5%
Step-by-step explanation:
Interest = 10100 - 8000 or 2100
I = Prt
2100 = 8000(9/12)r
2100 = 600r
2100/600 = r
3.5 = r
