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Ivahew [28]
2 years ago
15

Y'all don't make fun of me or anything my brains not working but this is a real question a triangle is 3 sides and a square has

4 right or is the other way around?
Mathematics
1 answer:
Xelga [282]2 years ago
3 0

Answer:

Lol, you're correct no worries!

Step-by-step explanation:

Yes a triangle has 3 sides and a square has 4 sides :)

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In the diagram, the radius of the outer circle is 5 centimeters and the area of the shaded region is 16π square centimeters. Fin
shusha [124]

Answer:

c because I did this one an yeah

8 0
2 years ago
Which of the following is the usually first step when using a general strategy for solving equations with fractions?
tester [92]

Answer:

A. multiply both sides by the LCD

Step-by-step explanation:

It helps cancel out fractions, making it easier to solve the equations

4 0
3 years ago
NEED HELP FAST PLZZ!!!!!!!
adell [148]
The answer is A. 102.  

Have a great day!
4 0
3 years ago
Solve for t<br><br> 4/3 = t/7
Mumz [18]

Answer:

\frac{28}{3}=t

Step-by-step explanation:

\frac{4}{3}=\frac{t}{7}

Use cross products to simplify the equation. Multiply the denominator of the second fraction by the numerator of the first fraction, and the denominator of the first fraction by the numerator of the second,

(4)(7) = (3)(t)

Simplify,

28=3t

Inverse operations,

\frac{28}{3}=t

4 0
2 years ago
How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
2x^2+14x+49=169

Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
2(x^2+7x-60)=0

Factor the Complex Trinomial:
2(x^2-5x+12x-60)=0

2(x(x-5)+12(x-5))=0

2(x-5)(x+12)=0

Set Factors to equal 0:
x-5=0

x=5

or

x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
\boxed{x=5}

I hope this helped!
-Benjamin

6 0
3 years ago
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