Answer:
It lies between 5 and 6
Step-by-step explanation:
![{ \tt{ \sqrt{30} = \sqrt{5 \times 3 \times 2} }} \\ \\ x={ \tt{ \sqrt{5} \times \sqrt{3} \times \sqrt{2} }} \\ \\ { \boxed{ \tt{= 5 < x < 6}}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7B%20%5Csqrt%7B30%7D%20%20%3D%20%20%5Csqrt%7B5%20%5Ctimes%203%20%5Ctimes%202%7D%20%7D%7D%20%5C%5C%20%20%20%5C%5C%20x%3D%7B%20%5Ctt%7B%20%5Csqrt%7B5%7D%20%20%20%5Ctimes%20%20%5Csqrt%7B3%7D%20%5Ctimes%20%20%5Csqrt%7B2%7D%20%20%7D%7D%20%5C%5C%20%20%5C%5C%20%20%7B%20%5Cboxed%7B%20%5Ctt%7B%3D%205%20%3C%20x%20%3C%206%7D%7D%7D)
x is the root of 30
Answer:
3
Step-by-step explanation:
Coefficient simply mean the multiplier of any alphabet or symbol or variable in a mathematical equation.
Therefore from the expression 3n-4, 3 is the multiple of n.
This simply implies that 3 is the coefficient of n.
Answer: Is this a question? Or statement Yes they can be angles
Step-by-step explanation:
Answer:
![-6Br^2-18r+Br+3](https://tex.z-dn.net/?f=-6Br%5E2-18r%2BBr%2B3)
Step-by-step explanation:
we have the expression:
![(6r-1)(- Br-3)](https://tex.z-dn.net/?f=%286r-1%29%28-%20Br-3%29)
We need to multiply the two terms in the first parenthesis by the two terms in the second parenthesis:
![(6r)(-Br)+(6r)(-3)+(-1)(-Br)+(-1)(-3)](https://tex.z-dn.net/?f=%286r%29%28-Br%29%2B%286r%29%28-3%29%2B%28-1%29%28-Br%29%2B%28-1%29%28-3%29)
we solve each term taking into account the law of signs
(-)(-)=+
and
(+)(-)=-
also for the first term we use that ![r*r=r^2](https://tex.z-dn.net/?f=r%2Ar%3Dr%5E2)
thus we have:
![-6Br^2-18r+Br+3](https://tex.z-dn.net/?f=-6Br%5E2-18r%2BBr%2B3)
it can be simplified a little more if we factor an r of the second and third term:
![-6Br^2+r(-18+B)+3](https://tex.z-dn.net/?f=-6Br%5E2%2Br%28-18%2BB%29%2B3)
1gal is bigger then 15 c if it had one more c it would be the same