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Marizza181 [45]

3 years ago

14

The side of a square is two raised to the seven halves power inches. using the area formula a = s2, determine the area of the sq

uare. a = 196 square inches a = 128 square inches a = 49 square inches a = 4 square inches

2 answers:

Deffense [45]3 years ago

8 0

A= 128 square inches

Hatshy [7]3 years ago

8 0

A=128 inches. this is the answer not option A. :)

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Oxana [17]

Answer:

3 : 4

Step-by-step explanation:

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2 years ago

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

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$P=AB+BC+CD+DH+HA$

we have

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substitute

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<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

so

Remember that $CH=x$

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$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

so

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

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Step-by-step explanation:

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The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1

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3 years ago

241 ten in base five?

igor_vitrenko [27]

241/5=48r1
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3 years ago