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kobusy [5.1K]
2 years ago
8

Que número disminuido en 32% es 520

Mathematics
1 answer:
seropon [69]2 years ago
3 0

Answer:

353.6

Step-by-step explanation:

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Round 863 to the nearest ten
anygoal [31]

Step-by-step explanation:

863 \approx \: 860

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3 years ago
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5y-x=10 solve for y
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5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

because
5y-x=5(2+\frac{x}{5})-x=5\cdot 2 +\frac{x}{\not5}\cdot 5 - x= 10+x-x=10



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3 years ago
If y varies inversely as the square of x, and y = 1/8 when x = 1, find y when x = 5.
Kisachek [45]
Y = k / x² ( y varies inversely as the square of x ) 
y = 1/8 when x = 1:
1/8 = k / 1²
8 k = 1
k = 1/8
For x = 5:
y = 1/8  / 5² = 1/8 : 25 = 1/8 · 1/25 = 1/200
Answer: A ) 1/200


6 0
3 years ago
In the mathematical expression 4 * 3 + 15 / 3 - 6, which operation is performed first?
sveta [45]
Multiplication would be first 
5 0
3 years ago
A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
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