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Anni [7]
3 years ago
6

4/7 of the birthday cake was eaten on your birthday. the next day your dad ate 1/2 of what was left. you get to finish the cake,

how much is left?
Mathematics
1 answer:
luda_lava [24]3 years ago
6 0
During the birthday 4/7 of the cake was eaten so it remained 1-4/7=3/7
the next day 1/2 of 3/7 was eaten what remained is 3/7 divide by 1/2
to divide we invert the second fraction (1/2) and multiply 3/7
3/7 x 2/1=6/7
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Brian has 16 yards of chain measured and cut at the. Hardware store. The chain will cost him 47.52$ how much is that per food? _
mojhsa [17]
3 feet= 1 yard

16*3= 48 feet.

47.52/48= 0.99

It will cost Brian $0.99 per foot. 

Find the unit rate. 

49.50/50= 0.99

No, it wouldn't. It would be the <em>same price 

0.99=0.99
It doesn't matter which one Brian chose. </em>

I hope this helps!
~kaikers
5 0
3 years ago
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Gnoma [55]

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3 years ago
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Evaluate the surface integral:S
rjkz [21]
Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle
\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle
\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v

So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
4 0
3 years ago
Which best summarizes the Pythagorean Theorem?
bezimeni [28]

Answer:

the bottom right one

Step-by-step explanation:

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HELP!! PLEASE EXPLAIN
yanalaym [24]

Answer:

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Step-by-step explanation:

basically you divide 7.5 by .75 which equals 10.

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3 0
2 years ago
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