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2 years ago

Can someone help me please

Mathematics

1 answer:

andrey2020 [161]2 years ago

7 0

Answer: y = 6

Step-by-step explanation:

A square's area can be done by using s^2, where s is y in this case. Because there are 5 squares, the area of the figure is 5y^2. Because the area is also 180cm, 5y^2=180.

Then divide both sides of the equation by 5 to get y^2 = 36. Then square root both sides of the equation to get y = 6.

Hope it helps <3

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-5n +8=-7 two step equations - intergers

vaieri [72.5K]

-5n + 8 = -7
-5n + 8 - 8 = -7 -8
-5n = -15
-5n/-5 = -15/-5
n = 3

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2 years ago

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

Tomtit [17]

Answer:

Option C.

Step-by-step explanation:

The given equations are

$3A-B=5$

$2A+3B=-4$

We need isolate one of the variables, such that it appears by itself on one side of the equation.

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

In equation 1, coefficient of B is 1. So, we can easily isolate one of the variables.

The equation is

$3A-B=5$

Subtract 3A from both sides.

$-B=5-3A$

Multiply both sides by -1.

$B=3A-5$

Therefore, the correct option is C.

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3 years ago

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Scilla [17]

Answer:

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2 years ago

Duncan shares 20 percent of all of his sales commissions with his personal assistant. If Duncan earns x dollars in commissions a

grandymaker [24]

Answer:

it b

Step-by-step explanation:

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2 years ago

to support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. t

Leokris [45]

Choice given:
<span>33.6°
39.8°
50.2°
56.4°

I drew the figure.
I got 12 ft as the hypotenuse, 10 ft as the opposite.

Sin</span>Θ = opposite / hypotenuse
SinΘ = 10/12
SinΘ = 0.83

I used the calculator to get the value of each angle using the sine function
sin(33.6°) = 0.55
sin(39.8°) = 0.64
sin(50.2°) = 0.77
sin(56.4°) = 0.83

The angle where the wire meets the ground is approximately 56.4°

8 0

3 years ago

Read 2 more answers

Can someone help me please ​

Can someone help me please