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harina [27]
3 years ago
9

What is 1/4 divided by 2/4

Mathematics
1 answer:
Alisiya [41]3 years ago
8 0
\dfrac{1}{4} \div  \dfrac{2}{4}

------------------------------------------------------------------------
Change the divide fraction to multiplication fraction :
------------------------------------------------------------------------

\dfrac{1}{4} \times  \dfrac{4}{2}

------------------------------------------------------------------------
Combine into single fraction :
------------------------------------------------------------------------

\dfrac{4}{8}

------------------------------------------------------------------------
Reduce to simplest form :
------------------------------------------------------------------------

\dfrac{4 \div 4}{8 \div 4} =  \dfrac{1}{2}

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Which of the following sets could be the sides of a right triangle?
o-na [289]

Answer:

1st answer

Step-by-step explanation:

From pythagorus theorem.

Since hypotenuse

=  \sqrt{  {2}^{2}  +  {3}^{2}  }=   \sqrt{ {13}}

4 0
3 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
What is the area of the parallelogram shown?
inna [77]
Area of the parallelogram
9 x 5
=45 cm squared
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP MARK AS BRAINLIEST
MatroZZZ [7]
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4 0
3 years ago
Find the first two random numbers (to the fifth digit after the decimal point) using linear congruential generator with a=4, m=1
yulyashka [42]

the first two random numbers are 4,5.using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed

linear congruential  generator

Xn= an-+b Lm

0d s = 25 , b=6, YM 11, 024

Q O o m) 4, Lu) = 4x2%U)

m= 4x4j = 5 y-5

the numbers are 4, 5.

4.O0000 5.000TO

A linear congruence generator is an algorithm that returns a sequence of pseudorandom numbers computed using discontinuous piecewise linear equations. This method is one of the oldest and best-known pseudorandom number generator algorithms.

The linear congruential generator (LCG) is a pseudorandom number generator (PRNG ) is a class of algorithms. Random number generation plays an important role in many applications, from cryptography to Monte Carlo methods.

Learn more about linear congruential here: brainly.com/question/3168048

#SPJ4

7 0
1 year ago
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