Beacause 35 is less than 39 the frezzing point of butter is closer to the frezzing point of water which is 0

Mathematics

2 answers:

maria [59]3 years ago

8 0

if 35 is LESS than 39

so +35 - 39 is -4 F°

the answer to the freezing point of (hehe) butter is -4 F°

ASHA 777 [7]3 years ago

7 0

Yes,your particular facts are right in this situation

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What does x equal x + 3 ≤ –5 + 2x

Anna [14]

X+3≤ -5+2x

Add 5 to the other side. (the inverse of subtraction, since 5 is negative)

x+8≤2x

Subtract x on both sides.

8≤x <- the answer

I hope this helps!
~kaikers

8 0

3 years ago

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masya89 [10]

Answer:

(8, 6)=(x, y) | (6, 5)= (y, x)

Step-by-step explanation:

Start at the x, and find the value. Next, find the value of y.

You already know the value for y is 6, so next find the value of x, which is 5.

7 0

2 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$