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bija089 [108]
3 years ago
10

Solve for z. 8z − 4 = 7z

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

8z − 4 = 7z

move 8z to the other side

sign changes from +8z to -8z

8z-8z-4=7z-8z

-4= 7z-8z

-4= -z

mutiply both sides by -1 to get +z

(-4)(-1)= (-z)(-1)

Answer:

z= 4

Salsk061 [2.6K]3 years ago
5 0

Answer:

you collect the like terms

8z -4=7z

-4=7z -8z

-4=-z

menus cancel menus

Z=4//

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∆DEF is similar to ∆ABC and the scale factor from ∆ABC to ∆DEF is 2. In ∆ABC, the largest angle measures 82º. Which measurements
Soloha48 [4]

Answer:

B

Step-by-step explanation:

the scale factor of 2 means the sides of Δ DEF are twice those of Δ ABC.

However, corresponding angles remain congruent , then

largest angle in Δ DEF is also 82°

5 0
2 years ago
Erin has $52 to spend at the florist. She wants to buy a vase for $11.75 and several roses for $3.50 each. What are the possible
Dennis_Churaev [7]

Answer:

12 roses

Step-by-step explanation:

$52 to spend at the florist

a vase for $11.75

roses for $3.50 each

Calculating how much left  after buying the vase:

$52 - $11.75 = $40.25

To Know the possible numbers of roses Erin can buy, divide:

$40.25 ÷$3.50 =  11,75, roundind 12 roses

4 0
3 years ago
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
4 years ago
Which is the greater one 9/10 or 3/4?
Hatshy [7]
9/10, 
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9/10 = 18/20
Clearly 9/10 is greater. 
4 0
3 years ago
Read 2 more answers
Please math expert simplify this thanks you
Svetllana [295]

Answer:

a-2

Step-by-step explanation:

6 0
3 years ago
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