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anastassius [24]

2 years ago

15

Kyleigh put a rectangular sticker on her notebook.the hiegth of the sticker measures 18cm.the base is half as long as the height

.what is the area of the notebook does the sticker cover

1 answer:

beks73 [17]2 years ago

7 0

The sticker covers 162 square cm.

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What is the value or x?

Romashka [77]

From the given figure

$\cos x=\frac{XY}{XZ}$

Since XY = 5.1 and XZ = 7.7, then

$\cos x=\frac{5.1}{7.7}$

To find x, use the inverse of cos

$x=\cos ^{-1}(\frac{5.1}{7.7})$

Use the calculator to find x

$x=48.522$

The answer is

4 0

8 months ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

2 years ago

A line passes through the points (-15, 4) and (5,8). What is its equation in slope-intercept

vovangra [49]

Answer:

y=1/5x+7

Step-by-step explanation:

just checked it on paper

7 0

2 years ago

Suppose that the demand equation for a certain item is 1p+1x2−160=0. evaluate the elasticity at 65:

bekas [8.4K]

Price elasticity is defined as $\frac{\Delta(quantity)}{\Delta(price)}$ .

Here, the question has omitted to define variables, so we will ASSUME
p=price
x=variable,
and we're given
p+x^2-160=0

We calculate
$\delta{x}/\delta{p}$ by implicit differentiation with respect to p:
1+2x (dx/dp)=0
=>
E(x)=(dx/dp)=-1/(2x)

Therefore the price elasticity at x=65 is
E(65)=1/(2*65) =-1/130 (approximately -0.00769)

4 0

2 years ago

Rewrite the expression using the Distributive Property.

Nostrana [21]

The Distributive Property states: a(b+c) = ab+ac.

5(6+12) is the expression.

5•6+5•12 is the product of the Distributive Property.

30+60 is the product of multiplication.

Therefore, 30+60 is the correct answer.

• We just distributed the 5 to the 6 and 12 because the entire expression of 6+12 is being multiplied by the 5, hence there are parentheses.

Feel free to mark Brainliest!

8 0

2 years ago