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2 years ago

(1 x2) x (3 x 2) x (1 x 3) = ?

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

8 0

Answer:

2*6*3= 36

Step-by-step explanation:

hope this helps

Multiply whats inside the prentices first, then multiply on the outside then that's how you will get your answer

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Please help me do the equation and figure out the right solution. I am supposed to be correcting the one in the picture.

alexira [117]

Answer:

The correct answer is if you want no roots in the denominator, the correct answer is $\frac{2x}{y}$ * $\sqrt[3]{2y^{2} }$

Step-by-step explanation:

The mistake is that you can't take a cube root of a square at step 3 when $y^{2}$ is taken out.

5 0

2 years ago

Simplfy <br> -3+(-10) <br> please explain how to do it too because i am lost in algebra.

Margaret [11]

Answer:
-13

you're basically adding -3 and -10 because they're both negatives

4 0

2 years ago

Of the 80 boys polled at lunch, 55% say they play video games daily. According to the poll, how many boys play video games daily

alexdok [17]

$55% = \frac{55}{100} = \frac{11}{20}$

Multiply $\frac{11}{20}$ by 80 and you will get how many boys play video games daily.

$\frac{11}{20}*80=\frac{11}{1}*4=11*4=44$

44 is the number of boys who play video games daily.

8 0

3 years ago

What is the following quotient?

Sophie [7]

√13 - √11

The last answer.

6 0

3 years ago

Read 2 more answers

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago