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777dan777 [17]
3 years ago
11

Triangle FGH with vertices F(1,8), G(5,7), and H(2,3) in the line y=x.

Mathematics
2 answers:
olganol [36]3 years ago
6 0

Answer:

F' (-1,8), G'(-5,7), H'(-2,3)

Step-by-step explanation:

sergiy2304 [10]3 years ago
4 0
Check Hathaway they will
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A parabola can be drawn given a focus of (6,-1) and a directrix of y = 9. What can be said about the parabola?​
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Answer:

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The vertex is halfway between the focus and the directrix, so the vertex is at (-6,-1).  (Draw this on graph paper if that doesn't make sense.)

 

The general form (conics form) of a parabola:  4p(y-k)=(x-h)^2 (vertex is (h,k) and "p" is the distance between the focus and vertex (or between vertex and directrix)).

 

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Step-by-step explanation:

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