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Zepler [3.9K]
3 years ago
12

There are 2 cell phone plans available from Cell phones R us company. Plan A charges 35$ a month plus $0.05 for every text messa

ge. Plan B charges $50 a month plus $0.01 for every text message. How many text messages do you need to send in order for plan A to be cheaper than plan B?
A.) 35 + 0.05m > 50 + 0.01m

B.) 35 + 0.05m > 50 + 0.01m

C.) 35 + 0.05m ≤ 50 + 0.01m

D.) 50 + 0.05m > 35 + 0.01m
Mathematics
2 answers:
kkurt [141]3 years ago
5 0
The correct inequality is letter a.
You have to send more than 375 text messages for Plan B be cheaper than plan A
likoan [24]3 years ago
5 0
Okay. I think you mean how many text messages must you send, until plan B is cheaper than plan A. Plan A is the one with the $30 fixed amount and plan B is the one with the $50 dollar fixed amount. The key words "cheaper than" means that our sign will be less than, not less than or equal to. Therefore, C is out.  We are looking for plan B ($50 fixed amount) to be less than. B and D are out, because those are greater than symbols toward plan B. A is the only one that shows the proper answer, and when you solve it right, you get m > 375. You would have to send 376 messages in order for plan B to be cheaper. The answer is A.
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valina [46]
1/6008
is the answer I believe
8 0
3 years ago
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Put this in descending order 3/8,-5/16,-0.65,2/4
vladimir1956 [14]

to solve this, you have to put all of the integers with a common denominator - so first put them all in a fraction

so all the fractions are:

3/8, -5/16, -3/20, 2/4

now put them all in a common denominator form over 320

120/320, -100/320, -48/320, 160/320

so negative numbers are the least so we'll leave them for the end (descending)

the order will now be:

160/320, 120/320, -48/320, -100/320,

now put these in the form of the real integers:

2/4, 3/8, -3/20, -15/16

8 0
3 years ago
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The relationship between ttt and rrr is expressed by the equation 2t+3r+6=02t+3r+6=02, t, plus, 3, r, plus, 6, equals, 0. If rrr
Greeley [361]

Question:

The relationship between t and r is expressed by the equation 2t+3r+6 = 0. If r increases by 4, which of the following statements about t must be true?

Answer:

The value of t is reduced by 6 when the value of r is increased by 4

Step-by-step explanation:

Given

2t + 3r + 6 = 0

Required

What happens when r is increased by 4

2t + 3r + 6 = 0 <em>-------- Equation 1</em>

Subtract 2t from both sides

2t + 3r + 6 - 2t = 0 - 2t

3r + 6 = - 2t --- <em>Equation 2</em>

When r is increased by 4, equation 1 becomes

2T + 3(r+4) + 6 = 0

Note that the increment of r also affects the value of t; hence, the new value of t is represented by T

Open bracket

2T + 3r+12 + 6 = 0

Rearrange

2T + 3r+6 +12 = 0

<em>Substitutr -2t for 3r + 6 [From equation 2]</em>

2T -2t +12 = 0

Make T the subject of formula

2T = 2t - 12

Divide both sides by 2

\frac{2T}{2} = \frac{2t - 12}{2}

T = t - 6

This means that the value of t is reduced by 6 when the value of r is increased by 4

3 0
3 years ago
Someone help me please
tamaranim1 [39]

Answer:

\sqrt{60}

Step-by-step explanation:

Use the Pythagorean theorem a^2 + b^2 = c^2

In this case you are given a and c, so set the equation up like

2^2 + b^2 = 8^2

b^2 = 8^2 - 2^2

b =\sqrt{8^{2} -2^{2} }

b =\sqrt{60}

6 0
2 years ago
X^2 is to 441 as x^3 is to
labwork [276]

X=perfect square of 441

= 21

X^3 = 21^3

=9261

8 0
3 years ago
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