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Zepler [3.9K]
3 years ago
12

There are 2 cell phone plans available from Cell phones R us company. Plan A charges 35$ a month plus $0.05 for every text messa

ge. Plan B charges $50 a month plus $0.01 for every text message. How many text messages do you need to send in order for plan A to be cheaper than plan B?
A.) 35 + 0.05m > 50 + 0.01m

B.) 35 + 0.05m > 50 + 0.01m

C.) 35 + 0.05m ≤ 50 + 0.01m

D.) 50 + 0.05m > 35 + 0.01m
Mathematics
2 answers:
kkurt [141]3 years ago
5 0
The correct inequality is letter a.
You have to send more than 375 text messages for Plan B be cheaper than plan A
likoan [24]3 years ago
5 0
Okay. I think you mean how many text messages must you send, until plan B is cheaper than plan A. Plan A is the one with the $30 fixed amount and plan B is the one with the $50 dollar fixed amount. The key words "cheaper than" means that our sign will be less than, not less than or equal to. Therefore, C is out.  We are looking for plan B ($50 fixed amount) to be less than. B and D are out, because those are greater than symbols toward plan B. A is the only one that shows the proper answer, and when you solve it right, you get m > 375. You would have to send 376 messages in order for plan B to be cheaper. The answer is A.
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Answer:

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Step-by-step explanation:

We need to find the LCM of 12 and 9.

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<u>Their LCM is:</u>

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Number of light fixtures and light bulbs is 36.

<u>Number of packages will be:</u>

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3 years ago
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Can u break it down and help me answer 13 and 15 thx
olya-2409 [2.1K]
13) The product is a name for the answer to a multiplication question.
6.65*10,000
=66500 (the decimal point moved 4 places to the right (you're multiplying) since they're 4 zeros in 10,00)

15) The quotient is a name for the answer to a division question.
2.374/100
=0.02374 ( the decimal point moved 2 places to the left ( you're dividing) since they're 2 zeros in 100)

Hope this helps! A thanks/brainiest answer would be appreciated :)




3 0
3 years ago
Explain why you cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds?
djyliett [7]

Answer:

We cannot calculate the probability  that a randomly selected passenger weighs more than 200 pounds

Step-by-step explanation:

We cannot calculate the probability  that a randomly selected passenger weighs more than 200 pounds because we do not know the number of possible outcomes, the events , sample space or the sample size. Probability is calculated  with frequency or occurrences or how much certainty there is.It is a number between 0 and 1. 1 indicates certainty and  0 indicates impossibility. Without a range or frequency how can we depict the possibility or impossibility of an occurrence of 200 pounds.

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A factor is one part of a product.

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here we have two terms: 15 and 20x

factors of first term 15 : since just one number is there so factors of 15 would be 1, 3, 5 and 15

factors of second term 20x: product of 20 and x gives 20x, so factors of 20x are 1,2,4,5, 10,20 and x

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Been stuck on this for a while now, some help would be nice.
vampirchik [111]

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20 total claustrophobic candy bars were in the machine

Step-by-step explanation:

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