1/6008
is the answer I believe
to solve this, you have to put all of the integers with a common denominator - so first put them all in a fraction
so all the fractions are:
3/8, -5/16, -3/20, 2/4
now put them all in a common denominator form over 320
120/320, -100/320, -48/320, 160/320
so negative numbers are the least so we'll leave them for the end (descending)
the order will now be:
160/320, 120/320, -48/320, -100/320,
now put these in the form of the real integers:
2/4, 3/8, -3/20, -15/16
Question:
The relationship between t and r is expressed by the equation 2t+3r+6 = 0. If r increases by 4, which of the following statements about t must be true?
Answer:
The value of t is reduced by 6 when the value of r is increased by 4
Step-by-step explanation:
Given

Required
What happens when r is increased by 4
<em>-------- Equation 1</em>
Subtract 2t from both sides

--- <em>Equation 2</em>
When r is increased by 4, equation 1 becomes
Note that the increment of r also affects the value of t; hence, the new value of t is represented by T
Open bracket
Rearrange

<em>Substitutr -2t for 3r + 6 [From equation 2]</em>

Make T the subject of formula

Divide both sides by 2


This means that the value of t is reduced by 6 when the value of r is increased by 4
Answer:

Step-by-step explanation:
Use the Pythagorean theorem a^2 + b^2 = c^2
In this case you are given a and c, so set the equation up like
2^2 + b^2 = 8^2
b^2 = 8^2 - 2^2
b =
b =