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scoray [572]
3 years ago
6

Help!! Lots of points

Mathematics
2 answers:
GuDViN [60]3 years ago
6 0

Answer:

The third option ||| Evaluate 5^2 and 2^2 ||| and the last option ||| Rewrite the expression as (5/2)^2 ||| are the correct choices.

So, C and E

murzikaleks [220]3 years ago
3 0

\frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2}) }^{2}
Since they are both squared.

Evaluating 5^2 and 2^2 and finding the quotient also works.

\frac{ {5}^{2} }{ {2}^{2} } =  \frac{5 \times 5}{2 \times 2}   =  \frac{25}{4}  = 6.25\\  \frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2} )}^{2}  = 2.5 \times 2.5 = 6.25
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.
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4x + y = 10<br> 7x + 2y = 17
Nezavi [6.7K]

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Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

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