All categories

3 years ago

Which number is prime 57, 63, 51, 67

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

Prime numbers cannot be broken down anymore, and are only have factors of it's own number and 1.

67 is your answer, as it can only be factored down to 67 x 1.

hope this helps

gavmur [86]3 years ago

4 0

The best answer would be D) 67 because the other numbers are not prime.

You might be interested in

If an angle is measured 76 what is the measure of its complementary angle?

zhuklara [117]

Answer:

Step-by-step explanation:

5 0

3 years ago

8.5cm squared = ...mm squared?<br><br> Please explain clearly

tekilochka [14]

1 centimeter = 10 milimeters.
Therefore, 8.5 centimeters squared = 85 millimeters squared.

6 0

3 years ago

Pls help for 27b!!!!!!!

rodikova [14]

Step-by-step explanation:

$\beta$

is a root of the quadratic

$4 {x}^{2} - 10x + 5$

This quadratic isn't factorable so use the quadratic formula

$- b + - \sqrt{ \frac{b {}^{2} - 4ac }{2a} }$

The plus and minus sign after b means we going to have two roots.

The roots are

$\frac{5 + \sqrt{5} }{4}$

and

$\frac{5 - \sqrt{5} }{4}$

We subsitue those values for Beta.

27a.

$\frac{5}{2}$

27b.

6 0

2 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

3 0

3 years ago

Type in expanded form. Use parentheses to indicate multiplication.<br><br> (-3x)^4

Mumz [18]

Negative 3x over the power by four

8 0

3 years ago