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PolarNik [594]
3 years ago
12

Which values are solutions to K-3 >-2? Select two options.

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Step-by-step explanation:

k‒3>‒2=k>‒2+3

=k>1

so there is not the answer here

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• Determine the coordinates of the vertices of the rectangle to compute the area of the rectangle using the distance formula (ro
sukhopar [10]

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the correct answer is d

Step-by-step explanation:

4 0
3 years ago
Evaluate. 2/3 - 1/6 <br> Please show an explanation.
Scorpion4ik [409]

Answer:

1/2

Step-by-step explanation:

2/3 - 1/6

Get a common denominator of 6

2/3 *2/2 - 1/6

4/6 - 1/6

3/6

Simplify

1/2

4 0
3 years ago
Read 2 more answers
Teru burned about 1,000 calories downhill skiing before lunch. If she plans to ski
Fudgin [204]

Answer:

3.3333 hours

Step-by-step explanation:

From the attached table :

Downhill skiing for 1/6 hours ; results in 100 calories burn

To burn 1000 calories :

Skiing hours required :

(1000 / 100) * (1/6)

10 * 1/6 = 10 /6 hours

Planned skiing hours = 5

Number of skiing hours after lunch will be :

5 hours - 10/6 hours

5 hours - 1.6666 hours

= 3.3333 hours

4 0
3 years ago
Surface area of a box 12 x 6 x 9.5
Ber [7]

9514 1404 393

Answer:

  486 square units

Step-by-step explanation:

Use the surface area formula with the given numbers.

  SA = 2(LW +H(L +W))

  SA = 2(12·6 +9.5(12 +6)) = 2(72 +9.5(18)) = 486

The surface area of the box is 486 square units.

4 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
3 years ago
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