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saveliy_v [14]
3 years ago
9

What is the equation in slope intercept form of the line that passes through the point (2,-2) and is perpendicular to the line b

y y=2/5x+2
Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

y= - 5/2x - 2

Step-by-step explanation:

Y=2/5x + 2

Making it perpendicular, the slope will change to it's reciprocal and swap operations (+ becomes -). 2/5 will be -5/2. We already know the y-intercept which is -2, so simply put, the equation in slope-intercept form is y = -5/2x - 2

Sophie [7]3 years ago
4 0

Answer:

  • y = -5/2x + 3

Step-by-step explanation:

<u>Given function:</u>

  • y = 2/5x + 2

Perpendicular lines have opposite reciprocal slopes.

The line that is perpendicular to the given will have a slope of -5/2.

<u>Now use the point (2, -2) and point-slope form to find the equation:</u>

  • y - (-2) = -5/2(x - 2)
  • y = -5/2x + 5 - 2
  • y = -5/2x + 3
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jok3333 [9.3K]
First, let's convert 0.77 to a fraction. 

\frac{0.77}{1}

Multiply by 100

\frac{77}{100}

Now make the denominators the same, to make it easier to find which fraction is greater. We can do this by finding the LCM of the denominators, then however many times the denominator goes into that number, we multiply the numerator by the same amount.

For example, the LCM of 100 and 6, is 300. 6 goes into 300 50 times, so the numerator for 4/6 is 200 (4 x 50 = 200). :)

\frac{200}{300} \ \textless \  \frac{231}{300}

The answer is 0.77 is greater than 4/6. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
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4 years ago
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Greatest to least 9, 1/2, -7, 0.75, -0.75,-5, 13
Vikentia [17]

Answer:

13, 9, 0.75, 1/2, -0.75, -5, -7

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Step-by-step explanation:

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Becky is 7 year older than half of Bryan's age. If Bryan is 36 how old is becky ?
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I THINK DONT QUOTE ME ON THAT ANSWER

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Wirte a decimal for each of the following 9x100+2x10+3x0.1+7x0.001
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Perform the indicated multiplication and addition.

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Math help plz! Giving brainlist :D
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-x^2+4x-4

dy/dx=-2x+4, d2y/dx2=-2

Since acceleration is a constant negative, when dy/dx, velocity, equals zero, it is at the absolute maximum value for f(x).

dy/dx=0 when -2x+4=0, 2x=4, x=2

f(2)=-x^2+4x-4=-4+8-4=0

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.5x^2+8x+5

dy/dx=x+8, d2y/dx2=1

Since d2y/dx2, acceleration is a constant positive, when dy/dx=0, it is at the point when f(x) is at an absolute minimum.

dy/dx=0 when x+8=0, x=-8

f(-8)=.5x^2+8x+5=32-64+5=-27

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-2(x+1)^2+5

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