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saveliy_v [14]
3 years ago
9

What is the equation in slope intercept form of the line that passes through the point (2,-2) and is perpendicular to the line b

y y=2/5x+2
Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

y= - 5/2x - 2

Step-by-step explanation:

Y=2/5x + 2

Making it perpendicular, the slope will change to it's reciprocal and swap operations (+ becomes -). 2/5 will be -5/2. We already know the y-intercept which is -2, so simply put, the equation in slope-intercept form is y = -5/2x - 2

Sophie [7]3 years ago
4 0

Answer:

  • y = -5/2x + 3

Step-by-step explanation:

<u>Given function:</u>

  • y = 2/5x + 2

Perpendicular lines have opposite reciprocal slopes.

The line that is perpendicular to the given will have a slope of -5/2.

<u>Now use the point (2, -2) and point-slope form to find the equation:</u>

  • y - (-2) = -5/2(x - 2)
  • y = -5/2x + 5 - 2
  • y = -5/2x + 3
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3 years ago
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If x+a is a factor of 2x²+2ax+5x+10,find a.
vazorg [7]

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Let's evaluate p(-a) and set it to zero:

2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2

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