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Flauer [41]
3 years ago
12

Sam can brew 5 gallons of root beer in an hour or he can make 4 pizzas in an hour. Ben can brew 7 gallons of root beer in an hou

r or he can make 5 pizzas in an hour.Who has an absolute advantage in making pizza?
Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

Ben

Step-by-step explanation:

Ben has an absolute advantage in making of pizza because he can make five pizzas in one hour which is a greater quantity compared to Sam that makes four pizzas in one hour.

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Label each fifth on the number line. )
Tcecarenko [31]

Step-by-step explanation:

1 for 0/5

2 for 1/5

4 for 2\5

4 for 3\5

4 for 4\5

12 for 5\5

1 for 6\5

1 for 7\5

1 for 8\5

6 0
3 years ago
Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. T
garik1379 [7]

Answer:

a) Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

b) t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

Step-by-step explanation:

Information given

\bar X=2.8 represent the sample mean

s=2.6 represent the population standard deviation  

n=1310 sample size  

\mu_o =3 represent the value to test

\alpha=0.5 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

3 0
3 years ago
Can I get provided with an explanation of how to work this out as well with the answer please ?
Yakvenalex [24]
Ummmmmmmmmmmmmmmmmmmmm ummmm uhhhhgh
4 0
3 years ago
How do I show the relationship between the input and the output
alexgriva [62]

Answer:

Types of Relationships between the Input and Output

The scatter plot can be a useful tool in understanding the type of relationship that exist between the inputs (X’s) and the outputs (Y’s)

Step-by-step explanation:

1. No Relationship: The scatter plot can give an obvious suggestion if the inputs and outputs on the graph are not related. The points will be scattered throughout the graph with no particular pattern. For no relationship to exist, points have to be completely diffused. If some points are in concentration, then maybe a relationship does exist and our analysis has not been able to uncover it.

2. Linear and Non-Linear: A linear correlation exists when all the points are plotted close together. They form a distinct line. On the other hand points could be close together but they could form a relationship which has curves in it. The nature of the relationship has wide ranging implications.

3. Positive and Negative: A positive relationship between the inputs and the outputs is one wherein more of one input leads to more of an output. This is also known as a direct relationship.

On the other hand a negative relationship is one where more of one input leads to less of another output. This is also known as an inverse relationship.

4. Strong and Weak: The strength of the correlation is tested by how closely the data fits the shape. For instance if all the points are scattered very close together to form a very visible line then the relationship is strongly linear. On the other hand, if the relationship does not so obviously fit the shape then the relationship is weak.

I don't know if this was exactly what you were looking for; hope it is! :)

7 0
3 years ago
How I can solve this
gavmur [86]

Answer:

\boxed{\textrm{B)}\qquad y>4}.

Step-by-step explanation:

We start by subtracting 1 from both sides of the second inequality:

2x > 5 \iff 2x - 1 > 5 - 1 \iff 2x - 1 > 4.

Therefore, we conclude that:

y > 2x - 1 > 4 \implies y > 4.

Therefore, every point that satisfies the system has a y-coordinate greater than 4.

7 0
4 years ago
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