The method of Problem 20 can be extended to second order equations with variable coefficients. If y1 is a known nonvanishing sol
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Answer:
(x, y ) = ( ,
)
Step-by-step explanation:
given the 2 equations
4x + 2y = 7 → (1)
y = 5x → (2)
Substitute y = 5x into equation (1)
4x + 2(5x) = 7
4x + 10x = 7
14x = 7 ( divide both sides by 14 )
x = =
substitute this value into equation (2)
y = 5 × =