The method of Problem 20 can be extended to second order equations with variable coefficients. If y1 is a known nonvanishing sol
1 answer:
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Answer:
By the Central Limit Theorem, the mean is 78, the standard deviation is and the shape is approximately normal.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 78 and a standard deviation of 6
This means that
Samples of n:
This means that the standard deviation is:
What are the mean, standard deviation, and shape of the distribution of x-bar for n?
By the Central Limit Theorem, the mean is 78, the standard deviation is and the shape is approximately normal.
Answer:
c) 62.
Step-by-step explanation:
Let x represent number of customers came in on the fifth day.
We have been given that the mean number of customers for those four days is 52. So total number of customers on 4 days would be 4 times 52 that is 208 customers.
We know that mean of a data set is equal to sum of all data points divided by number of data points.
Total number of customers on 5 days would be and total number of days is 5.
Since we need a mean of 54, so we can set mean of 5 days equal to 54 as:
Multiply both sides by 5:
Therefore, 62 customers must come in on the fifth day to make the five-day mean 54 and option 'c' is the correct choice.