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3 years ago

What is the most reasonable estimate for 54% of 168 A:8.4 B:46 C:84 D:110

2 answers:

8 0

Just by estimating, 54% is a little over 1/2 of 168. You know by that, that neither A or B is close. The real answer is 90.72, so if your instructor wants you to round up, it would be D

Makovka662 [10]3 years ago

6 0

C 84. In a quick number crunch your first move is to find 50% of 160 which is 80. The only number above half is 84 so since we need 54% then 84 is the correct answer

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Robert is already 50 miles from his home on his way to the game he is driving 55 miles per an hour

ASHA 777 [7]

i would need more details!

what is the answer?

3 0

3 years ago

Marta has $10 more than twice as much money as Heidi has. Together they have $36. How many money does each girl how. how does He

professor190 [17]

x=heidi

x + (2x+10)=36

3x +10=36

3x -10 -10

3x=26

x=8.6 heidi has 8.6

marta has 27.3

5 0

3 years ago

One of the more famous anecdotes in the field of statistics is known as the "Lady Tasting Tea" and involves the renowned statist

mote1985 [20]

Answer:

$n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36$

And rounded up we have that n=8068

Step-by-step explanation:

The margin of error for the proportion interval is given by this:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

We want for this case a 95% of confidence desired, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for this case is $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The estimated proportion for this case is $\hat p=0.3$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.3(1-0.3)}{(\frac{0.01}{1.96})^2}=8067.36$

And rounded up we have that n=8068

7 0

3 years ago

Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce

pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0

4 years ago

What number squared equals 1.5

Stolb23 [73]

You have to find out what is the square root of 1.5 is which is <span>1.22474487139 by calculator to make sure of this, do answer squared and you will get 1.5</span>

8 0

3 years ago

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