Answer:
Q1
cos 59° = x/16
x = 16 cos 59°
x = 8.24
Q2
BC is given 23 mi
Maybe AB is needed
AB = √34² + 23² = 41 (rounded)
Q3
BC² = AB² - AC²
BC = √(37² - 12²) = 35
Q4
Let the angle is x
cos x = 19/20
x = arccos (19/20)
x = 18.2° (rounded)
Q5
See attached
Added point D and segments AD and DC to help with calculation
BC² = BD² + DC² = (AB + AD)² + DC²
Find the length of added red segments
AD = AC cos 65° = 14 cos 65° = 5.9
DC = AC sin 65° = 14 sin 65° = 12.7
Now we can find the value of BC
BC² = (19 + 5.9)² + 12.7²
BC = √781.3
BC = 28.0 yd
All calculations are rounded
Answer:
9x2x1 and 6x3x1
Step-by-step explanation:
This question has multiple answers to it. A sandbox of 18 cubic feet with a height of a foot is actually quite simple. If it is confusing I would try to visualize the sandbox. Since volume is b x h x w the first thing you should do is divide 18 by 1. This would be more important if the height was more than one. Now you just have to find two other numbers that can divide 18. 9x2=18 and 6x3=18 so two possible dimensions for the sandbox are 9x2x1 and 6x3x1
Answer:
solution given :
Since opposite side and side of a congruent triangle are equal.
Now
the statement which is true is:
<HDG=~ <HFE
Sample space = 17 + 7 + 4 = 28
P(pink) = 7/28
P(orange) = 17/28
P(pink or orange) = P(pink) + P(orange)
P(pink or orange) = 7/28 + 17/28
P(pink or orange) = 24/28
P(pink or orange) = 6/7 or 0.857143 or 85.7%
