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Elden [556K]
3 years ago
7

A square garden has 49 square feet. So the perimeter of the garden must be----feet.

Mathematics
2 answers:
lianna [129]3 years ago
7 0

The side length of a square is the square root of the area:

Side length = √49 = 7 feet.

The perimeter of a square is 4s = 4*7 = 28 feet.

babymother [125]3 years ago
5 0

Answer:

28

Step-by-step explanation:

If the area of the garden is 49 ft^2 and all sides are equal because it's a square, we can take the square root of 49 to get a side length.

The square root of 49 ft^2 is 7 ft.

Since there are 4 sides to a square, we multiply the length of one side by the number of sides to get the total perimeter.

4 x 7 ft = 28 feet total

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A. 4<br> b. 5<br> c. 9<br> d. 25
trapecia [35]
5t=45
45/5=9

The answer is C
Hope I helped
7 0
3 years ago
According to the Central Limit Theorem, which statements(s) are TRUE. There may be more than 1 correct answer. A. An increase in
Liono4ka [1.6K]

Answer:

Options A, B and C are correct.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

From the Central Limit Theorem, we have that:

The larger the sample size, the closer to the normal distribution the distribution of sample means is.

No matter the sample size, the mean is the same.

The larger the sample size, the smaller the standard deviation.

The smaller the sample size, the larger the standard deviation.

So the correct options are:

A, B, C

6 0
3 years ago
Write 230.251 in expanded form
Tamiku [17]
200+30+0.2+0.05+0.001=230.251
5 0
3 years ago
Read 2 more answers
A football coach is trying to decide: When a team is ahead late in the game,
brilliants [131]

Answer:

I play football and my coach will do this: Play a "prevent* defense that guards against long gains but makes short

gains easier.

Step-by-step explanation:

8 0
2 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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