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dsp73
2 years ago
15

OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is th

e scale factor of enlargement.​

Mathematics
1 answer:
bazaltina [42]2 years ago
6 0

Answer:

(D) 2

Step-by-step explanation:

The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC

Therefore, we have;

The \ scale \ factor = \dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}}

\dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{2 \ units}{1 \ unit} = 2

\dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{4 \ units}{2 \ units} = 2

\dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}} =  \dfrac{2 \cdot \sqrt{5}  \ units}{\sqrt{5}  \ units} = 2

Therefore, the scale factor = 2

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Find sin X, sin Z, cos X, and cos Z. Write each answer as a simplified fraction.
just olya [345]

Answer:

Find the answers below

Step-by-step explanation:

Using m<X as the reference angle

Opposite YZ = 7

Adjacent  XY = 10

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinX = opp/hyp

sinX =YZ/XZ

sinX = 7/√149

For cos X

cos X = adj/hyp

cos X =10/√149

Using m<Z as reference angle;

Opposite XY = 10

Adjacent  YZ = 7

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinZ = opp/hyp

sinZ =10/√149

sinZ = 7/√149

For cos Z

cosZ = 7/√149

7 0
2 years ago
What is the area of the sector? Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter
n200080 [17]

Question:

What is the area of the sector? Either enter an exact answer in terms of π or use 3.14 and enter your answer as a decimal rounded to the nearest hundredth.

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the values of radius and central angle are not given.

However, I'll answer the question using the attached figure.

From the attached figure, the radius is 3 unit and the central angle is 120 degrees

The area of a sector is calculated as thus;

Area = \frac{\alpha }{360} * \pi r^2

Where \alpha represents the central angle and r represents the radius

By substituting \alpha = 120 and r = 3

Area = \frac{\alpha }{360} * \pi r^2 becomes

Area = \frac{120}{360} * \pi * 3^2

Area = \frac{1}{3} * \pi * 9

Area = \pi * 3

Area = 3\pi square units

Solving further to leave answer as a decimal; we have to substitute 3.14 for \pi

So, Area = 3\pi becomes

Area = 3 * 3.14

Area = 9.42 square units

Hence, the area of the sector in the attached figure is 3\pi or 9.42 square units

8 0
3 years ago
Can somebody please help me? :(
Natasha2012 [34]

Answer:

143 square meters

Step-by-step explanation:

The surface has a width of 11 meters and a length of 13 meters.

13 x 11 = 143.

Is this correct?

5 0
2 years ago
The ratio of a to b is 9:2, and the ratio of c to b is 5:3. What is the ratio of a to c?
xz_007 [3.2K]
The answer is that the ratio of a to c is 9/5
8 0
2 years ago
ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2. If the perimeter of ΔMNO is 25 units, what's the perimeter o
KIM [24]

Answer:

b)37.5

Step-by-step explanation:

the ratio 3:2 is the same as 1.5, so you  multiply 1.5 & 25 to get 37.5 units

7 0
3 years ago
Read 2 more answers
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