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dsp73
3 years ago
15

OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is th

e scale factor of enlargement.​

Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

(D) 2

Step-by-step explanation:

The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC

Therefore, we have;

The \ scale \ factor = \dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}}

\dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{2 \ units}{1 \ unit} = 2

\dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{4 \ units}{2 \ units} = 2

\dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}} =  \dfrac{2 \cdot \sqrt{5}  \ units}{\sqrt{5}  \ units} = 2

Therefore, the scale factor = 2

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Step-by-step explanation:

A system of equations is 2 or more equations for which the same x,y solution exists. We can solve the system in three ways: elimination, substitution, or graphing. Substitution can be used by substituting the value of one variable into the equation.

<u>Pair x=3y-5 and x+y=3</u>

Because x=3y-5, we can substitute 3y-5 into x in x+y=3

x+y=3

(3y-5)+y=3

3y-5+y=3

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We now substitute y=2 into x=3y-5.

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<u>Pair y=x and 3x+3y=18</u>

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3x+3y=18

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We now substitute x=3 into y=x.

y=3.

<u>Pair y=-3x+4 and 5x-y=0</u>

Because y=-3x+4, we can substitute -3x+4 into y in 5x-y=0

5x-y=0

5x-(-3x+4)=0

5x+3x+4=0

8x+4=0

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We now substitute x=-1/2 into y=-3x+4

y=-3x+4

y=-3(-1/2)+4

y=3/2+4

y=11/2


4 0
4 years ago
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