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Paha777 [63]
3 years ago
11

Find another name for the given number but with the denominator indicated use multiplying by 1. 1/2 = ?/10

Mathematics
1 answer:
liq [111]3 years ago
6 0
5/10 because it is equivalent to 1/2

So the answer is 5/10
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The product of a number and 50
Daniel [21]
"Product" means we are looking at a multiplication problem.

Can be written as: 

A number (n) times 50

n x 50

The simplest (and most common way) to write it:

50n
4 0
3 years ago
Read 2 more answers
How can you write the outer dimension of the walkway?
UNO [17]
4/5/8/87/7/9 is the answer
7 0
3 years ago
10+z=x what is the answer
Basile [38]

First you had subtract by ten from both sides of equation form.

10+z-10=x-10

Then simplify by equation.

z=x-10

Final answer: \boxed{z=x-10}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

8 0
3 years ago
HELP! Given a pyramid l = w = 9.0 mm and V = 324.0 cubic mm , find h in mm
harina [27]

Answer:

The answer to your question is height = 12 mm

Step-by-step explanation:

Data

l = w = 9 mm

V = 324 mm³

h = ?

Formula

V = \frac{Ab x h}{3}

Solve for h

                       3V = Ab h

                       3V / Ab = h    or     h = 3V / Ab

Find the area of the base

Ab = l x w

     = 9 x 9

     = 81 mm²

Substitution

                       h = \frac{3(324)}{81}

Simplification

                       h = \frac{972}{81}

Result

                       h = 12 mm                    

3 0
3 years ago
HELP HELP HELP HELP HELP HELP PLZZ<br> SOMEONE
velikii [3]

Answer:

B.) 4.18 square inches

Step-by-step explanation:

Find the area of the one right triangle and multiply it by two. The formula for the area of a triangle is:

A=\frac{1}{2} bh

Insert the values. 1.1 is the base and 3.8 is the height:

A=\frac{1}{2} *1.1*3.8

Simplify:

A=\frac{1*1.1*3.8}{2} \\\\A=\frac{4.18}{2} \\\\A=2.09

Multiply the area of one triangle by two:

2.09*2=4.18\\\\A=4.18

The total area of the shaded figures is 4.18 in^2

:Done

8 0
3 years ago
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