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Paha777 [63]
3 years ago
11

Find another name for the given number but with the denominator indicated use multiplying by 1. 1/2 = ?/10

Mathematics
1 answer:
liq [111]3 years ago
6 0
5/10 because it is equivalent to 1/2

So the answer is 5/10
You might be interested in
A(3-x)=-2x+B if x=2 How do I find A and B what are the answers
irina1246 [14]

Answer:

A=5,B=9\\\\or\ A=-9,B=-5

Step-by-step explanation:

A(3-x)=-2x+B\\\\Given\ x=2\\\\Substitute\ the\ value\ of\ x\\\\A(3-2)=-2\times 2+B\\\\A=-4+B\\\\A=B-4\\\\So\ the\ value\ of\ A\ is\ 4\ less\ than\ the\ value\ of\ B.\\\\When\ B=9\Rightarrow A=9-4=5\\\\When\ B=-5\Rightarrow B=-5-4=-9\\\\Hence\ A=5,B=9\\\\or\ A=-9,B=-5

4 0
3 years ago
What is v?<br> -15V-40 = 23-8V
Andrew [12]

Answer:

V = -9

Step-by-step explanation:

-15V - 40 = 23 - 8V

The objective is to get V alone. To do this, first subtract -15V from both sides. Since -15V is a negative, subtracting it will be adding a positive.

-40 = 23 + 7V

Now that there is only one term with the variable V, subtract 23 from both sides.

-63 = 7V

Finally, divide both sides by 7 to get V completely isolated.

-9 = V.

The final answer is V = -9.

7 0
3 years ago
Read 2 more answers
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
An on-demand movie company charges $2.95 per movie plus a monthly fee of $39.95. Which expression represents the yearly
MakcuM [25]

Answer: 2.95x+39.95(12)

Step-by-step explanation:

Hi, to answer this question we have t write an expression with the information given:

The yearly cost for x movie rentals is equal to : the product of the cost of each movie (2.95) and the number of movies (x) ;plus the product of the monthly fee (39.95) and the number of months in a year (12)

Mathematically speaking:

2.95x+39.95(12)

5 0
4 years ago
Read 2 more answers
What is the distance between the points (−5, −9)(−5, −9) and (−5, 13)(−5, 13) ?
krok68 [10]
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-5,-9)...x1 = -5, and y1 = -9
(-5,13)...x2 = -5 and y2 = 13
now we sub and solve
d = sqrt (-5 - (-5)^2 + (13 - (-9)^2
d = sqrt (-5 + 5)^2 + (13 + 9)^2
d = sqrt (0^2 + 22^2)
d = sqrt (484)
d = 22 <==
6 0
3 years ago
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