If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
CHEESE
Step-by-step explanation:
CHEESE IS ALWAYS THE ANSWER!!!
The remainder is or answer is 6
The answer is some number between 9 and 10.
Explanation:
√83
is an irrational number. You won't be able to simplify it any further either, since it doesn't have any perfect square factors.
However, you will be able to tell between which two numbers it lies in.
9^2 is 81 and 10^2 is 100
. Therefore, you can say that a certain number between 9 and 10 is 83 when squared.
If you're looking for an exact answer, then it will be 9.11043357914... (I got that using a calculator).
