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nignag [31]
3 years ago
9

Choose the expressions that are sums or differences of two cubes.

Mathematics
2 answers:
jonny [76]3 years ago
7 0
It is the top three, you know this because they factor easily into cubes, so the answer is the top three, i did this on my assignment and it was correct, Purple math explains it
Volgvan3 years ago
3 0

Answer:

only (1) , (2) and (3) can be written as sums or differences of two cubes

Step-by-step explanation:

Given : Some expressions.

We have to choose the expressions that are sums or differences of two cubes.

The sums or differences of two cubes is written as

a^3-b^3 and a^3+b^3

1)  64+a^{12}b^{51}

64 can written as 64=4^3 and a^{12}b^{51}=(a^4b^{17})^3

So,  64+a^{12}b^{51} can be written as (4)^3+(a^4b^{17})^3

2) -t^6+u^3v^{21}

-t^6 can written as -t^6=(-t^2)^3  and u^3v^{21}=(uv^{7})^3

So, -t^6+u^3v^{21} can be written as (-t^2)^3+(uv^{7})^3

3) 8h^{45}-k^{15}

8h^{45} can written as 8h^{45}=(2\sqrt{2}h^{15})^3 and  k^{15}=(k^5)^3

So, 8h^{45}-k^{15} can be written as (2\sqrt{2}h^{15})^3-(k^5)^3

 

Thus, only (1) , (2) and (3) can be written as sums or differences of two cubes

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The table shows the distance the students a group of students walked during after-school practice. What was the total distance,
ser-zykov [4K]

First let's convert the decimal numbers to mixed numbers:

\begin{gathered} 3.4=3+0.4=3+\frac{4}{10}=3+\frac{2}{5}=3\frac{2}{5} \\ 1.75=1+0.75=1+\frac{75}{100}=1+\frac{3}{4}=1\frac{3}{4} \\ 2.25=2+0.25=2+\frac{25}{100}=2+\frac{1}{4}=2\frac{1}{4} \end{gathered}

Now, adding all the numbers, we have:

\begin{gathered} (3+\frac{2}{5})+(3+\frac{1}{5})+(1+\frac{3}{4})+(2+\frac{1}{4})+(1+\frac{7}{10}) \\ =(3+3+1+2+1)+(\frac{2}{5}+\frac{1}{5}+\frac{3}{4}+\frac{1}{4}+\frac{7}{10}) \\ =10+(\frac{3}{5}+1+\frac{7}{10}) \\ =11+(\frac{6}{10}+\frac{7}{10}) \\ =11+\frac{13}{10} \\ =12+\frac{3}{10}=12\frac{3}{10} \end{gathered}

So the correct option is B.

8 0
1 year ago
Nsider the following system of equations y=6x^2+1, y=x^2+4
sp2606 [1]

The given equations are y= 6x^2+1 and y=x^2+4

Both the equations equal y so we can make them equal

6x^2+1=x^2+4

To bring x term on one side we subtract x^2 both sides

6x^2-x^2+1=4

5x^2+1=4

To isolate x term we subtract 1 both sides

5x^2=4-1

5x^2=3

Dividing by 5 both sides

X^2=3/5

Taking root of both sides we have:

X=±√⅗

Substituting x value to find y

When x=+√⅗=0.7745

Y= 6x^2+1

Y=6(3/5)+1

Y= 18/5+1

Y=23/5 =4.6

When x= -√⅗=-0.7745

Y= 6(3/5)+1

Y=23/5=4.6

Point of intersections are ( 0.7745,4.6) and (-0.7745,4.6)

7 0
3 years ago
Will mark as brainliest if correct
Oduvanchick [21]

Answer:

X=0

Step-by-step explanation:

Anything raised to the power of 0 is 1.

4 0
4 years ago
Instructions: Find the equation of the line through point (−4,1) and parallel to y=−12x−2. Use a forward slash (i.e. "/") for fr
USPshnik [31]

Answer:

y = - 12x - 47

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 12x - 2 ← is in slope- intercept form

with slope m = - 12

Parallel lines have equal slopes, thus

y = - 12x + c ← is the partial equation

To find c substitute (- 4, 1 ) into the partial equation

1 = 48 + c ⇒ c = 1 - 48 = - 47

y = - 12x - 47 ← equation of parallel line

7 0
4 years ago
Use synthetic division to solve (2x^3+4x^2-35x+15)/(x-3). What is the quotient?
amm1812

Answer:

the quotient is 2x^2+10x-5

5 0
3 years ago
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