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BARSIC [14]
3 years ago
11

Two cars leave from the same point at the same time, one traveling east and the other traveling west.

Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0
Car travelling to the east is at 104 miles per hour and the car travelling to the west is moving at 114 miles per hour
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elena55 [62]

Answer:

d

Step-by-step explanation:

because it is promotional

6 0
3 years ago
Read 2 more answers
The table and scatter plot below show the number of hits and runs Tyler's baseball team got in each of 12 tournament games.
agasfer [191]

The correct statements are:

  • There is a positive linear equation between the number of hits and the scores
  • The point (7,13) is an outlier.
  • If the trend continues, for a game when Tyler's team gets 20 hits, the number of runs scored would be greater than 10 hits.

<h3>What are the correct statements?</h3>

An outlier is a number that is way smaller or way larger than that of other numbers in a data set. On a trend line, an outlier would be far from the trendline.

A positive linear relationship is when as one of the variables increase, the other variable also increases and the trendline is a straight line that is upward sloping.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

3 0
3 years ago
3c=1/27. what does c equal?
Rainbow [258]

Answer:

9

Step-by-step explanation: 3*9=27 and 27 divided by 1 =27

7 0
4 years ago
I can’t figure out what it is asking. How do you find where each line crosses the y-axis?..
frez [133]
The y axis is the vertical line
3 0
4 years ago
Help with this..but not Pauline helms she is unhelpful tutor.
romanna [79]

Since the tangent of B is 4/3, then:

\begin{gathered} \frac{AC}{BA}=\frac{4}{3} \\ \Rightarrow AC=\frac{4}{3}BA \end{gathered}

On the other hand, since ABC is a right triangle with hypotenuse BC, then:

(BA)^2+(AC)^2=(BC)^2

Substitute AC=3/4 BA and BC=15 to find BA:

\begin{gathered} (BA)^2+(\frac{4}{3}BA)^2=15^2 \\ \Rightarrow BA^2+\frac{16}{9}BA^2=15^2 \\ \Rightarrow(1+\frac{16}{9})BA^2=15^2 \\ \Rightarrow\frac{25}{9}BA^2=15^2 \\ \Rightarrow BA^2=\frac{9}{25}\cdot15^2 \\ \Rightarrow BA=\sqrt[]{(\frac{9}{25}\cdot15^2)} \\ \Rightarrow BA=\frac{3}{5}\cdot15 \\ \Rightarrow BA=9 \end{gathered}

Substitute BA=12 into the expression for AC to find its value:

AC=\frac{4}{3}BA=\frac{4}{3}(9)=12

On the other hand, we know that:

BD+DA=BA

Substitute BA=12 and DA=3 to find BD:

\begin{gathered} BD+3=9 \\ \Rightarrow BD=9-3 \\ \Rightarrow BD=6 \end{gathered}

Finally, since BDE and BAC are similar triangles, we know that:

\begin{gathered} \frac{DE}{BD}=\frac{AC}{BA} \\ \Rightarrow DE=\frac{AC}{BA}\times BD \end{gathered}

Substitute AC=12, BA=9 and BD=6 to find the length DE:

\begin{gathered} DE=\frac{12}{9}\times6 \\ \Rightarrow DE=8 \end{gathered}

Therefore, the length of DE is:

8

3 0
1 year ago
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