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BARSIC [14]
3 years ago
11

Two cars leave from the same point at the same time, one traveling east and the other traveling west.

Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0
Car travelling to the east is at 104 miles per hour and the car travelling to the west is moving at 114 miles per hour
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f - 1 (x)  = - 2 (1 + x)/2 + x Hope this help's :)

Step-by-step explanation:


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3 years ago
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Step-by-step explanation:

4 0
3 years ago
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What number is in the ten-thousandths spot of pi?
Nesterboy [21]

Answer:To figure out the value you have to look at all of the numbers from right to left.  You start with the ones place and get prgressively bigger going up by a multiple of 10 each time.  So you have the ones, tens, hundreds, thousands, ten thousands, etc.  In the number in your example, you have 3 ones, 4 tens (or 40), 1 hundred or (100), 0 thousands, and 5 ten thousands (50, 000).  You can write the number in expanded form to help you figure out the value.  50,000 + 100 + 40 +3.  

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8 0
3 years ago
A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei
Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

6 0
2 years ago
Eugenia walked all the way to school at 3 mph then realized she forgot her math book (how could she?!), so she ran back at 7 mph
kondor19780726 [428]

Let us say distance between Eugenia's home and school is x miles.

Speed of Eugenia when she walked from home to school = 3 mph

Speed of Eugenia when she walked from school to home = 7 mph

Total time taken = 45 minutes or 0.75 hours

We know that the speed distance formula is given by:

speed=\frac{distance}{time}

time=\frac{distance}{speed}

Time taken by Eugenia when she walked from home to school = x/3 hours

Time taken by Eugenia when she walked from school to home = x/7 hours

Total time taken = x/3+x/7

So forming an equation we have,

\frac{x}{3}+\frac{x}{7}=0.75

Taking lcd of 7 and 3 as 21,

\frac{7x}{21}+\frac{3x}{21}=0.75

\frac{10x}{21}=0.75

10x=15.75

Dividing both sides by 10 , we have

x= 1.575

Answer: So we can say that the distance between Eugenia's house and school is 1.575 miles.




4 0
3 years ago
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