3 years ago

Can somebody help me?

Mathematics

2 answers:

N76 [4]3 years ago

8 0

Answer:smsjsjsjsjsjss

Step-by-step explanation:idididididisjsnsbuxxjhx

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Ymorist [56]3 years ago

8 0

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Let the ladder length be L, then

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the length of ladder is 21.3 feet

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A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

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$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$

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