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3 years ago

What is when you divide 33-55 divide by 11 will egual

1 answer:

8 0

So if you means 33-55=-22
-22/11=x

so when dividing by a negative, just divide as usual, but just make the answer negative so

-22/11=22/11 times -1/1=2 times -1=-2

the answer is -2

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6 0

1 year ago

Find the value of x

GuDViN [60]

Answer:

x = 12

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

3x+19 + 5x = 115

Combine like terms

8x + 19 = 115

Subtract 19 from each side

8x+19 -19 = 115 -19

8x = 96

Divide each side by 8

8x/8 = 96/8

x =12

7 0

3 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

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3 years ago

Explain why f(x) = x2+4/x2-x-2 is not continuous at x = 2.

xxTIMURxx [149]

Answer: Option a.

Step-by-step explanation:

Make the denominator equal to zero and solve for x:

Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:

$x^{2}-x-2=0\\(x-2)(x+1)=0\\x=2\\x=-1$

Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2

The answer is the option a.

6 0

3 years ago

Read 2 more answers

Can someone answer this question please?

allochka39001 [22]

Answer:

Step-by-step explanation:9

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3 years ago