<em>The distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>
<h2>Explanation:</h2>
Endpoints of a Line segments are places where they end or stop. Line segments are named after their endpoints. In this case, those endpoints are Y and Z, so the line segment would be:

To find the length of this segment with endpoints Y(2, 8) and Z(-2, 5), let's use the Distance Formula:


Finally, <em>the distance the length of a segment with endpoints Y(2, 8) and Z(-2, 5) is 5 units</em>
<h2>Learn more:</h2>
Distance Formula: brainly.com/question/10134840
#LearnWithBrainly
This is an arithmetic sequence because each term is 7 greater than the previous term, so 7 is what is called the common difference...
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=first term, d=common difference, n=term number.
We know a=1 and d=7 so:
a(n)=1+7(n-1)
a(n)=1+7n-7
a(n)=7n-6
The above is the "rule" for the nth term.
I=prt
20=p X .05 X 5
20 = p X .25
20/.25 = p
80 = p
She started with $80
So we got the real axis and the imaginary axis
we just need to find the average of the 2 points
remember
midpoint of (x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
so
average of 3 and -8 is -5/2
average of -5i and 2i is -3/2i
center is -5/2-3/2i