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miss Akunina [59]
4 years ago
8

Can anyone help solve this exponents/logarithm question

Mathematics
1 answer:
m_a_m_a [10]4 years ago
3 0

Answer:

x=0.355

Step-by-step explanation:

5^5x=4^3-2x

5x=6log_{6}(2)-4log_{6}(2)x\\\\5x+4log_{6}(2)x=6log_{6}(2)\\\\(5+4log_{6}(2))x=6log_{6}(2)\\\\x=\frac{6log_{6}(2)}{5+4log_{6}(2)}\\\\x=\frac{6log_{6}(2)}{log_{6}(6^{5})+log_{6}(2^{4} )}\\\\x=\frac{6log_{6}(2)}{log_{6}(6^{5}*2^{4})}\\\\x=\frac{6log_{6}(2)}{log_{6}(16*6^{5})}\\\\x=6log_{16*6^{5}}(2)\\\\x=6log_{124416}(2)\\\\6log_{124416}(2)=0.354509\\\\

3 decimal places of 0.354509 is 0.355

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3 years ago
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jalapeño

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to check your work you can do

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And equation of a straight line is   y = mx + c  or   y – y1 = m(x – x1)

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the equation can be rewritten as  h – h1  = m(t – t1)                    (1)

So, to find the equation of line , first we will calculate the slope of the line.

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Learn more about the straight line here : brainly.com/question/6977417

#SPJ4

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