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3 years ago

Add these mixed numbers 4 4/7+3 2/7

Mathematics

2 answers:

Ksju [112]3 years ago

8 0

Answer:

50/7 or 7 1/7

Step-by-step explanation:

liubo4ka [24]3 years ago

3 0

The answer is 7 6/7 since you’re just adding the whole numbers and fractions.

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F(x)=x^2. What is g(x)? <br>A. g(x)=1/4x^2<br>B. g(x)=1/2x^2<br>C. g(x)=(1/2x)^2<br>D. g(x)=2x^2

murzikaleks [220]

Answer:

The answer is b g(x)=1/2x^2

Step-by-step explanation:

7 0

3 years ago

A flower garden is in the shape of a parallelogram. The base of the parallelogram is eight feet, and it's height is five feet. W

amid [387]

Area of a paralleligram equalls height into base. in this case it would be 8×5.

area=h×b
=8×5
=40feet squared
answer= 40 feet squared
hope this helps.....

6 0

4 years ago

What is it AHHH HELP‼️

TEA [102]

Answer

5.5cm

Step-by-step explanation:

The radius of a circle is the distance from the center of the circle to any point on its circumference.

The easiest way to find the radius is by dividing the diameter in half.

Radius = 1/2 × diameter

Here diameter is given as 11 cm.

Hence Radius = 1/2 × 11 cm.

= 11/2 cm.

= 5.5 cm.

5 0

3 years ago

Read 2 more answers

Solve for x if log 9 base x + log 3 base x^2 = 2.5

Y_Kistochka [10]

Not sure if the equation is

$\log_9x+\log_3(x^2)=\dfrac52$

$\log_x9+\log_{x^2}3=\dfrac52$

If it's the first one:

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}$

$9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}$

$9^{\log_9x+\log_3(x^2)}=x\cdot x^4$

$9^{\log_9x+\log_3(x^2)}=x^5$

On the other side of the equation, we'd get

$9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5$

Then

$x^5=3^5\implies\boxed{x=3}$

If it's the second one instead, you can use the same strategy as above:

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}$

(Note that this step assume $x>0$ )

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}$

$x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}$

$x^{\log_x9+\log_{x^2}3}=9\sqrt3$

Then we get

$9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}$

6 0

3 years ago

John bought a tv for 1280 and had to pay7% tax. he also recieved a 5% rebate what did he pay

Alex777 [14]

Let's assume the rebate is applied only to the 1280 and not the tax, so John pays a net 2% additional, tax less rebate.

1.02 × 1280 = 1305.06

Answer: 1305.06

8 0

3 years ago