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Anna007 [38]
4 years ago
8

Why is the information in the diagram enough to determine that △LMN ~ △PON using a rotation about point N and a dilation? becaus

e both triangles appear to be equilateral because∠MNL and ∠ONP are congruent angles because one pair of congruent corresponding angles is sufficient to determine similar triangles because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN
Mathematics
2 answers:
Gala2k [10]4 years ago
8 0
To determine that:
                              △LMN ≅  △PON

We would rotate the figure about point N and a dilation.

The best answer choice is :

<span>C. </span>because one pair of congruent corresponding angles is sufficient to determine similar triangles.

Here are rules of rotation:

Rotate 90 counterclockwise =  (x, y) → (–y, x)

Rotate 180 counterclockwise = (x, y) → (–x, –y)

Rotate 270 counterclockwise = (x, y) → (y, –x) 

skelet666 [1.2K]4 years ago
6 0
The answer would be C
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Find derivative problem<br> Find B’(6)
dalvyx [7]

Answer:

B^\prime(6) \approx -28.17

Step-by-step explanation:

We have:

\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]

We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t

Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

Therefore:

\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0
3 years ago
Paul biked 55 miles in 10 hours . what is the unit rate of miles per hour
irinina [24]

Answer:

5.5 miles per hour

Step-by-step explanation:

Since he travels a total of 55 miles in 10 hours, you need to divide.

55/10 = 5.5

total hours/total miles = miles per hour

3 0
3 years ago
Read 2 more answers
The coordinates of A and B are (3k, 8) and (k, -3) respectively. Given that the gradient of the line segment AB is 3, find the v
Vladimir [108]

Step-by-step explanation:

gradient = slope or several other words.

it describes how strongly a line (or tangent to a bent curve) is going up or down or ... if it is changing at all.

it is represented by the ratio

(y coordinate change / x coordinate change)

when going from one point on the line to another.

in our case, when going from A to B we have

x changes by -2k (from 3k to k).

y changes by -11 (from 8 to -3).

so, the gradient or slope is

-11/-2k = 3

11/2k = 3

11 = 3×2k = 6k

k = 11/6

A = (33/6, 8) = (11/2, 8)

B = (11/6, -3)

5 0
2 years ago
What is the area of the square?
Vsevolod [243]
C. 84
12 x 8 is the area of the whole thing but you subtract 12 because of the missing 6x2 part of the square
4 0
3 years ago
The price of 10 citrons and 7 fragrant wood apples is 55 units. The price of 7 citrons and 10 fragrant wood apples is 64 units.
a_sh-v [17]

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Further explanation:

Let x be the price of one citron and

y be the price of one fragrant

Then according to given statement

10x+7y = 55         Eqn 1

7x+10y = 64          Eqn 2

Multiplying equation 1 by 7

7(10x+7y) = 7(55)\\70x+49y=385

This will be equation 3.

Multiplying equation 2 by 10

10(7x+10y) = 10(64)\\70x+100y=640

This will be equation 4.

Subtracting equation 3 from equation 4

70x+100y - (70x+49y) = 640-385\\70x+100y-70y-49y = 255\\51y = 255\\\frac{51x}{51} = \frac{255}{51}\\x = 5\\Putting\ x=5\ in\ equation\ 1\\10(5)+7y = 55\\50+7y = 55\\7y = 55-50\\7y = 5\\\frac{7y}{7} =\frac{5}{7}

So,

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Keywords: Linear Equations, Solving system of linear equations

Learn more about linear equations at:

  • brainly.com/question/13168205
  • brainly.com/question/1357167
  • brainly.com/question/1542444

#LearnwithBrainly

5 0
3 years ago
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