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3 years ago

I NEED ANSWERS ASAP!!!!! Please help I don't understand this at all!!!

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

7 0

On function 1 - plot the points onto the graph and get your answer

On function 2 - use the answer to work in reverse to get your plot points and graph filled in

On function 3 - grab plotted points and put them in the graph

tamaranim1 [39]3 years ago

5 0

The first one you need to draw the line that the graph makes and at the bottom you put the slope and y-intersect. the 2nd one you use the parent function for X which is -2, -1, 0, 1, and you plug those numbers into the bottom equation to get your y's then graph the line. the 3rd one is the same to where you use the points that it gives you to determine the x and y values while figuring out the slope and y-intercept on the bottom.

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What are the exact steps to solve for the x-intercepts of f(x)= −4x2 + 4x + 8? What about −9 = x2 + 6x? Please explain thoroughl

victus00 [196]

Answer:

x-intercepts: (-1, 0) and (2, 0)

x-intercept: (-3, 0)

Step-by-step explanation:

Given quadratic function:

$f(x)=-4x^2+4x+8$

The x-intercepts of a quadratic function are the points at which the curve crosses the x-axis ⇒ when y = 0

Therefore, to find the x-intercepts of the given function, set the function to zero:

$\implies -4x^2+4x+8=0$

Factor out -4:

$\implies -4(x^2-x-2)=0$

Divide both sides by -4

$\implies x^2-x-2=0$

Rewrite the middle term as -2x + x:

$\implies x^2-2x+x-2=0$

Factor the first two terms and the last two terms separately:

$\implies x(x-2)+1(x-2)=0$

Factor out the common term (x - 2):

$\implies (x+1)(x-2)=0$

Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}(x+1) & = 0 & \quad \textsf{ or } \quad \quad (x-2) & = 0\\\implies x & = -1 & \implies x & = 2\end{aligned}$

Therefore, the x-intercepts are (-1, 0) and (2, 0).

---------------------------------------------------------------------------------------

Given quadratic equation:

$-9 = x^2 + 6x$

Add 9 to both sides:

$\implies x^2+6x+9=0$

Rewrite the middle term as 3x + 3x:

$\implies x^2+3x+3x+9$

Factor the first two terms and the last two terms separately:

$\implies x(x+3)+3(x+3)=0$

Factor out the common term (x + 3):

$\implies (x+3)(x+3)=0$

$\implies (x+3)^2=0$

Square root both sides:

$\implies (x+3)=0$

Solve for x:

$\implies x=-3$

Therefore, the x-intercept is (-3, 0).

As the function has a repeated factor (multiplicity of two), the curve will touch the x-axis at (-3, 0) and bounce off.

3 0

2 years ago

What would happen if someone sarhpled a basketball team to find the

GarryVolchara [31]

Answer:

Basketball players are normally taller so it would not be accurate

6 0

3 years ago

Read 2 more answers

Select the best answer for the question

Klio2033 [76]

Answer:

C. $\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]$

Step-by-step explanation:

The given matrices are;

$F=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]$

and

$C=\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]$

$FC=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]$

$FC=\left[\begin{array}{ccc}12(-2)+0(1)&0(-2)+-6(0)&\frac{3}{2}(-2)+7(0)\\12(0)+8(1)&0(0)+8(-6)&0(\frac{3}{2})+8(7)\\2(12)+1(1)&2(0)+1(-6)&2(\frac{3}{2})+1(7)\end{array}\right]$

This simplifies to;

$FC=\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]$

The correct answer is C

5 0

3 years ago

Solve 8. Will mark brainless if correct. Would appreciate some help!

Molodets [167]

Answer:

Step-by-step explanation:

$(2x^{5} )^3\\2x^{5} *2x^{5} *2x^{5} \\8x^{15}$

This is your answer

Hope this helps!

6 0

3 years ago

How much is the tree worth?

noname [10]

Answer:

Step-by-step explanation:

Deer = snow flake = 4

4 + 4 + 4 = 12

Dear - 3 = 1

Snowman = 1

Tree = 8

8 + 1 (snowman) + 8 = 17

8 0

3 years ago