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NikAS [45]
3 years ago
5

Karlena is on an old cell phone plan. The cost of a call depends on the number of minutes the phone call lasts. She can use the

expression $0.10m+3.500.10m+3.50 to find the cost of a call. If m is the number of minutes, which of the following best describes $3.50?
The total cost of a call


A fee that is charged per call


The cost per minute


How long the call lasted
Mathematics
1 answer:
enot [183]3 years ago
7 0
A few that is charged per call.
It’s the constant which means that it isn’t going to change. It can’t be the total cost because there is no equal sign. It can’t be the cost per minute because the x represents the minutes, which means .1 represents the cost. Lastly it cannot be how long the call lasted because m is the minutes which is the length of the call.
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Tresa drew a quadrilateral with two pairs of parallel sides and four right angles what what quadrilateral could she have drawn
oksian1 [2.3K]

Rectangle and square
8 0
3 years ago
Insert 5 arithmetic means between -1 and 11
Anni [7]

Answer:

Step-by-step explanation:

-1 1 3 5 7 9 11

That's the answer. If you need a method or a formula, that's a little harder.

L = a + (n - 1)*d

a = -1

L = 11

n = 7

or n is the hard part. If you have 5 means, then you have 6 spaces. So n must be 7 in all

11 = -1 + (7 - 1)*d                   add 1 to both sides. Combine the brackets

11+1 = -1+1+ 6*d

12 = 6d                               divide by 6

12/6 = d

2 = d

What this tells you is that each term has 2 added to it to get to the next one.

   

7 0
3 years ago
EXAMPLE 3 Show that the curvature of a circle of radius k is 1/k. SOLUTION We can take the circle to have center the origin, and
Anastasy [175]

Answer:

Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j  and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.

Step-by-step explanation:

We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.

Now, using the derivatives of sines and cosines, and the definition of norm,  we obtain that:

r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1

T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1

6 0
4 years ago
ALGEBRAIC PROOF PLEASE HELP IT IS MY LAST QUESTION I AM STUMPED
zepelin [54]
3x +0 can be replaced by 3x because of "the additive identity property of real numbers: anything plus zero is that thing."
5 0
3 years ago
The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100 What is the st
anzhelika [568]

Sample standard deviation

Mean of data = 84.4

Calculate deviations from the mean = 23.4, 17.8, 3.4, 1.4, -2.6, -3.6, -4.6, -5.6, -13.6 and -15.6

Squaring these deviations; we get 547.56, 316.84, 11.56, 1.96, 6.76, 12.96, 21.15, 31.36, 184.96, 243.36

Adding these we get 1378.47

As its a sample Std Dev we divide by 10 - 1 = 9. For the popklation Std Dev we divide by the number of scores (10).

Std Deviation for sample = sqrt ( 1378.47 / 9) = 12.4 to nearest tenth (answer)

Population Std Dev = sqrt (1378.47 / 10) = 11.7 answer

Theres a lot of arithmetic there so hope i haven't slipped up anywhere!

6 0
3 years ago
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