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emmainna [20.7K]
3 years ago
15

The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100 What is the st

andard deviation, to the nearest tenth, of the data if the scores represent a sample of Mr. Smith's students? _______a0 What is the standard deviation, to the nearest tenth, of the data if the scores represent the entire population of Mr. Smith's students? __________ a1
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Sample standard deviation

Mean of data = 84.4

Calculate deviations from the mean = 23.4, 17.8, 3.4, 1.4, -2.6, -3.6, -4.6, -5.6, -13.6 and -15.6

Squaring these deviations; we get 547.56, 316.84, 11.56, 1.96, 6.76, 12.96, 21.15, 31.36, 184.96, 243.36

Adding these we get 1378.47

As its a sample Std Dev we divide by 10 - 1 = 9. For the popklation Std Dev we divide by the number of scores (10).

Std Deviation for sample = sqrt ( 1378.47 / 9) = 12.4 to nearest tenth (answer)

Population Std Dev = sqrt (1378.47 / 10) = 11.7 answer

Theres a lot of arithmetic there so hope i haven't slipped up anywhere!

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57°
noname [10]

Answer:

c = 29

Step-by-step explanation:

Law of sines is given as: \frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)}

B = 180 - (57 + 44) = 79°

b = 41

C = 44°

c = ?

Thus:

\frac{b}{sin(B)} = \frac{c}{sin(C)}

Substitute

\frac{41}{sin(79)} = \frac{c}{sin(44)}

Multiply both sides by sin 44

\frac{41}{sin(79)}*sin(44) = \frac{c}{sin(44)}*sin(44)

\frac{41*sin(44)}{sin(79)}*sin(44) = c

c = 29.0140633 ≈ 29

3 0
3 years ago
Brainliest for you if you answer!
eduard

<u>To find the constant of proportionality:</u>

  ⇒ must define constant of proportionality

    ⇒ <em>Constant of Proportionality:  ratio of two proportional values at a </em>

       constant value

       ⇒ (in this case) two proportional values are x and y

<u>The ratio between x and y is equal to</u>

  \frac{y}{x} =\frac{66}{1.2}=55

<u>Answer:</u> <u>55</u> or <u>Choice 1</u>

<u></u>

Hope that helps!

7 0
2 years ago
HURRY!!!!!!!!!<br><br> Given P(5,10,8) and Q(7,11,10), find the midpoint of the segment PQ.
rusak2 [61]

Answer:

P_{m}=(6,10.5,9)

Step-by-step explanation:

The mid point can be found with the formula

P_{m}=(\frac{x_{1}+x_{2} }{2},\frac{y_{1} +y_{2} }{2} ,\frac{z_{1}+z_{2}  }{2} )

The given coordinates are P(5,10,8) and Q(7,11,10).

Replacing coordinates in the formula, we have

P_{m}=(\frac{5+7}{2},\frac{10+11 }{2} ,\frac{8+10}{2} )=(\frac{12}{2},\frac{21 }{2} ,\frac{18}{2} )\\P_{m}=(6,10.5,9)

Therefore, the mid point of the segment PQ is P_{m}=(6,10.5,9)

4 0
3 years ago
(01.02 LC)Simplify negative 3 and 1 over 9 − negative 8 and 1 over 3.
blsea [12.9K]

As we are given with

-3\frac{1}{9}-(-8\frac{1}{3})\\\\

we are supposed to simplify this expression. which can be done as below

\\=-3\frac{1}{9}+8\frac{1}{3}\\\\=\frac{-28}{9}+\frac{25}{3}\\\\=\frac{-28+75}{9}\\\\=-\frac{47}{9}\\

=5\frac{2}{9}

6 0
3 years ago
Can you please give me the answer
IrinaK [193]

Step-by-step explanation:

This will help okay! I promise you, well I hope .

6 0
3 years ago
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