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sp2606 [1]
3 years ago
6

A particular model of walkie-talkie can broadcast in a circular area. The radius of the broadcast area is 10,000 feet.

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0
I think thatv  the answer is  a 314,000,000 ft ^2
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Four runners are training for long races. Noah Ran 5.123 miles. Andre ran 6.34 miles. Jada ran 7.1 miles. Diego ran 8 miles.
Korolek [52]
Jada ran 1.977 miles more than Noah
3 0
3 years ago
Which of these systems of equations would be best solved using the subtraction​ method?
Lynna [10]

Answer:

Step-by-step explanation:

1. x+2y=6 or x=6-2y

3x-2y=2

3(6-2y)-2y=2

18-6y-2y=2

18-8y=2

-8y=-18+2

-8y=-16

y=-16/-8

y=2 ans.

x+2*2=6

x+4=6

x=6-4=2 ans.

Proof:

3*2-2*2=2

6-4=2

2=2

I leave the rest for you to practice with.

3. 4x+y=7

2x+5y=-1

 

5. 3x+2y=-2

6x-y=6

Solve the system using the elimination method. Show all your steps.

7. -3x+3y=3

3x+y=9 add.

---------------------------------

4y=12

y=12/4

y=3 ans.

3x+3=9

3x=9-3

3x=6

x=6/3

x=2 ans.

Proof:

-3*2+3*3=3

-6+9=3

3=3

I'll leave the rest for practice.

9. -5x+12y=20

x-2y=-6

11. 3x+2y=1

4x+ 6y= 7

4 0
2 years ago
Five less than the product of 7 and a number is equal to 3.
mr Goodwill [35]

Answer:

x = 8/7

Step-by-step explanation:

Step 1: Convert to math

7x - 5 = 3

Step 2: Solve for <em>x</em>

  1. Add to both sides: 7x = 8
  2. Divide both sides by 7: x = 8/7
6 0
3 years ago
How Would you define the term scatter plot?
pogonyaev
Scatter Plot<span>. ... A </span>graph<span> of plotted points that show the relationship between two sets of data. In this example, each dot represents one person's weight versus their height</span>
7 0
3 years ago
Read 2 more answers
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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