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MAVERICK [17]
3 years ago
13

Please answer correctly !!!!Will mark brainliest !!!!!!!!!!!!!!

Mathematics
2 answers:
Leya [2.2K]3 years ago
5 0

Answer:

option B

Step-by-step explanation:

  • x+2y=2 ⇒x= 2- 2y
  • 2x+4y=-8 ⇒ 2(2-2y) +4y= -8 ⇒ 4-4y+4y= -8 ⇒ 4= -8 this is impossible
  • so no solutions

Answer: option B

saveliy_v [14]3 years ago
4 0

Answer:

No solutions

Step-by-step explanation:

x + 2y and 2x + 4y are linear combinations of each other since 2 ( x + 2y ) = 2x + 4y.

However, since 2 ( x + 2y = 2 ) results in 2x + 4y = 4 and the second equation reads as 2x + 4y = -8, there is no solution to this system of equations since 4 does not equal -8.

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Read 2 more answers
If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0
3 years ago
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