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Korolek [52]
3 years ago
10

Which problem can be solved using 3x7=21 give me a example

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

21/7= 3

Step-by-step explanation:


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$570, 2%, 6 months <br> -<br> Help, I don’t get how to do it.
Phantasy [73]

Answer:

$641.91

Step-by-step explanation:

A(t) = 570(1+0.02)^6

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No problem 72 cubic squares
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Help with 1-3 show work on how got the answer to be marked as brainliest
MatroZZZ [7]
B.) 10 The length of the board is 7×12 = 84
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7 0
3 years ago
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
Solve $16x+9=9y-2x$ for $y$ .
s344n2d4d5 [400]

Answer:

The solution for y is y = 2x + 1

Step-by-step explanation:

* <em>Lets explain how to solve an equation for one of the variables</em>

- We need to solve the equation 16x + 9 = 9y - 2 x for y

- That means we want to find y in terms of x and the numerical term

- the equation has two sides, one side contains x and numerical term

 and the other side contains y and x

- We need to separate y in one side, and other term in the other side

* <em>Lets do that</em>

∵ 16x + 9 = 9y - 2x

- Add 2x to both sides to cancel -2x from the right side

∴ 16x + 2x + 9 = 9y - 2x + 2x

- Add like terms in each side

∴ 18x + 9 = 9y

- Divide each term by the coefficient of y ⇒ (÷9)

∴ (18 ÷ 9)x + (9 ÷ 9) = (9 ÷ 9)y

∴ 2x + 1 = y

- Switch the two sides

∴ y = 2x + 1

* The solution for y is y = 2x + 1

3 0
3 years ago
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