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Korolek [52]
3 years ago
10

Which problem can be solved using 3x7=21 give me a example

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

21/7= 3

Step-by-step explanation:


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For the following right triangle, find the side length x. Round your answer to the nearest hundredth. Side 15 bottom x 25 upper
sattari [20]

Answer:

x = 20

Step-by-step explanation:

To do this question, you can use the pythagorean theorem.  c is your hypotenuse, a is the unknown side length and b is the known side length.

a^2+b^2=c^2

x^2+15^2=25^2

x^2=225=625

x^2=400

(x^2)^(1/2)=400^(1/2)

x = 20

8 0
3 years ago
Multiply and simplify: sq rt 7x ((sq rt x)-7sq rt. 7)
jarptica [38.1K]
7x(√x - 7√7) Multiply √7x to "√x" and "-7√7" respectively: 
√7x*√x - 7√7*√7x 
First is to simplify: √7x² - 7√7²x 
Extract the squares: x√7 - 7*7√x 

Then, we simplify: x√7 - 49√x 
After simplifying the equation, I got the answer x√7 - 49√x.
3 0
3 years ago
Read 2 more answers
How is Social Security calculated?
Evgesh-ka [11]
I think 1, because you need age for receive that document
8 0
3 years ago
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In analyzing hits by certain bombs in a​ war, an area was partitioned into 553 ​regions, each with an area of 0.95 km2. A total
Leto [7]

Answer:

Probability of having two hits in the same region = 0.178

mu: average number of hits per region

x: number of hits

e: mathematical constant approximately equal to 2.71828.

Step-by-step explanation:

We can describe the probability of k events with the Poisson distribution, expressed as:

P(x=k)=\frac{\mu^ke^{-\mu}}{k!}

Being μ the expected rate of events.

If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

\mu=\frac{\#bombs}{\#regions} =\frac{535}{553}= 0.9674

For a region to being hit by two bombs, it has a probability of:

P(x=2)=\frac{\mu^2e^{-\mu}}{2!}=\frac{0.9674^2e^{-0.9674}}{2!}=\frac{0.9359*0.38}{2}=0.178

4 0
3 years ago
in 2013 the population of detroit was 743204 the population of the city of detroit in the year 1970 was 688,701 greater than in
Virty [35]

Answer:

The population of Detroit in 1970 was 1,431,905 people.

Step-by-step explanation:

Take the number 743,204 and add the number 688,701.

7 0
3 years ago
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