To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

$Area = Length \times Width$

Rectangle (a)

$Area = 4x \times 4$

$Area = 16x$

Rectangle (b)

$Area = 11 \times x$

$Area = 11x$

Rectangle (c)

$Area = 2 \times 8x$

$Area = 16x$

Rectangle (d)

$Area = 16x \times 1$

$Area = 16x$

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

7 0

2 years ago

Find the x-intercepts/roots of the polynomial function. Also, identify the degree of the polynomial

Mrac [35]

Answer:

Step-by-step explanation:

roots=-2,-1,1,3

critical points=(-1.5,-3),(0,6),(2,-13)

absolute minimum=-13

End behavior :approaches +infinity

Relative max=6 at (0,6)

Relative min. =-3 at (-1.5,-3)

and -13 at (2,-13)

interval of increase=(-1.5,0)∪(2,∞)

interval of decrease=(-∞,-1.5)∪(0,4)

roots=-1,2

critical points=(0.5,10.5),(4,-10.5)

Abs.max/abs.min=not defined

End behavior:-∞ to +∞

Relative max=10.5

Relative min=-10.5

interval of increase=(-∞,0.5) ∪ (4,∞)

interval of decrease=(0.5,4)

4 0

2 years ago

Round 7.365 to the ones place.​

Round 7.365 to the ones place.