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2 years ago

Four students grafted one linear function each

Mathematics

1 answer:

Brut [27]2 years ago

8 0

Step-by-step explanation:

The answer is attached in this photo

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1. Use a property of exponents to write (3b)⁵ as a product of powers. 2. What is the width of the rectangle written as an expone

motikmotik

Answer:

Step-by-step explanation:

1. (3b)^5

= (3b)^2 * (3b)^3.

2. Width = area / length

= 10^4 / 10^3

= 10^(4-3)

= 10 m.

8 0

3 years ago

Solve for missing sides of a right triangle using the pythagorean theorem of 6 and 11 and x

Fantom [35]

Each side has own formula, so which side is X

6 0

3 years ago

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The volume of a rectangular box is found by multiplying its length, width, and height: V = lwh. A certain box has a volume of b

vlada-n [284]

I think its (b+3) (b+2) (b-2) maybe wrong not sure

5 0

2 years ago

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

$m_ {1} * m_ {2} = - 1$

The given line is:

$5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3$

So we have:

$m_ {1} = \frac {5} {2}$

We find $m_ {2}:$ $m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}$

So, a line perpendicular to the one given is of the form:

$y = - \frac {2} {5} x + b$

We substitute the given point to find "b":

$-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2$

Finally we have:

$y = - \frac {2} {5} x-2$

In point-slope form we have:

$y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)$

ANswer:

$y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)$

3 0

2 years ago

Read 2 more answers

Which expression shows that the quotient

Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is $\frac{2}{(3x-1)}$ ÷ $\frac{6}{6x-1}$

We further simplify this expression,

$\frac{2}{(3x-1)}$ ÷ $\frac{6}{6x-1}$

= $\frac{2}{(3x-1)}\times \frac{6x-1}{6}$

= $\frac{6x-1}{3(3x-1)}$

= $\frac{6x-1}{(9x-3)}$

Therefore, $\frac{6x-1}{(9x-3)}$ will be the quotient of the given expression.

$x\neq \frac{1}{3}$ and $x\neq \frac{1}{6}$ for which the given expression is not defined.

Option (2) will be the answer.

6 0

3 years ago