Answer:
First shift - 1101
Second shift - 0110
Third shift - 1011
Fourth shift - 1101
Fifth shift - 0110
Sixth shift - 1011
Explanation:
Each time you shift a register to the right, you do 3 things:
- The rightmost digit drops off
- You move the next three digits over one position to the right
- You fill in the leftmost position with one of the numbers from your serial input.
Contents are initially 1011. The 1 on the right disappears. The leftmost 3 digits (101) end up in the last 3 positions of the register. The first position of the register takes a number from the serial input, which is 1 in this case. So you end up with 1101.
Do this a second time. The rightmost 1 is gone, the 110 end up as the last 3 positions of the register, and you end up with 0 in the leftmost position. This one is 0110.
The remaining 4 follow the same pattern.
I don’t know if I am right but I think it d am i right
Answer:
AGGHHHHHHHHHHHHHHHHHHHGHGHHHHHH
Explanation:
Answer:
The answer is letter B. Will fail without user commitment
Explanation:
With an old IT adage in mind, even a perfect IT program<em> Will fail without user commitment. Because the glaring vulnerability in the security architeture of ECM systems is that few protections exist once the information is legitimately accessed. These confidential information often can be printed, e-mailed, or faxed to unauthorized parties without any security attached.</em>
ans . B a collection of similar fonts
