Answer:
The answer is "None of these".
Explanation:
In the given question an array "sales[]" is declared, which contains 50 double type elements, and in the next line, an integer variable j is defined, which uses a for loop. In this question two options is given, in which both are not correct, that can be described as follows:
- In option (i), A loop is defined that, uses variable j which starts with 0 and ends with 48, So total elements are 48 that's why it is not correct.
- In option (ii), A loop will use variable j that, starts with 1 and ends with 49, That's why it is not correct.
1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}
2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}
3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}
4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}
5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}
Answer:
64 K bytes = 65536 bytes
32 M bytes = 33554432 bytes
Explanation:
The question expect the number of bytes in binary instead of decimal. So this is important to understand that:
- 1K bytes = 1024 bytes (in binary)
Therefore,
- 64 Kb = 64 x 1024 = 65536 bytes
Using the similar calculation logic, we know
- 1M bytes = 1024 x 1024 = 1048576 bytes (in binary)
Therefore,
- 32 M bytes = 32 x 1048576 = 33554432 bytes
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
operation = input("Which operation are you performing? (a/s/m/d) ")
if operation == "a":
print("{} + {} = {}".format(num1, num2, num1+num2))
elif operation == "s":
print("{} - {} = {}".format(num1, num2, num1-num2))
elif operation == "m":
print("{} * {} = {}".format(num1, num2, num1*num2))
elif operation == "d":
print("{} / {} = {}".format(num1, num2, num1/num2))
I hope this helps!
