Answer:
22045278
Step-by-step explanation:
5 8 2 9
<u> 3 7 8 2</u>
11 6 5 8
4 6 6 3 2 0
4 0 8 0 3 0 0
<u>1 7 4 8 7 0 0 0</u>
2 2 0 4 5 2 7 8
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Answer:
Find attached missing part of the question:
The option gpe is best when the contracted volume is below 31250 units
The option fms is best when the contracted volume is between 31,250 and 230,000 units
The option DM is best when contracted volume is above 230,000 units
Step-by-step explanation:
let x represent the volume produced in each of the three options:
Total cost(TC) =fixed cost+(variable per unit*x)
for general purpose equipment:
TC=125,000+18x equation 1
for flexible manufacturing system
TC=250,000+14x equation 2
for dedicated machine
TC=480,000+13x equation 3
if we set equations 1 and 2 together
125,000+18x=250,000+14x
If we equate equations 2 and 3 together
250,000+14x=480,000+13x
14x-13x=480,000-250,000
x=230,000
18x-14x=250,000-125,000
4x=125,000
divide both sides y 4
x=125,000/4=31250
Answer:
12x^2-5x-2
Step-by-step explanation:
An interesting question!
Instead of solving each set of non-linear system of equations 6 times, I will try a simpler way, which is more adapted to multiple choice questions. However, please be warned that this method will not improve immensely math skills, but will help with reasoning, and possibly a broader understand in system of equations.
For simplicity, I will denote the sets of system of non-linear equations by S={A,B,C,D,E,F} from left to right.
1. given solutions {(-2,3),(7,-6)}
We first check each member of S, i.e. A,B,C,D,E,F for the linear conditions.
A: x+y=-2+3=1 ≠ 3 so no
B: x-y=-2-3=-5 ≠ 1 so no
C: 2x+y=-2(2)+3=-1 ≠ 1 so no
D: x+2y=-2+3(2)=4 ≠ 2 so no
E: -x+y=2+3=5 ≠ 1 so no
F: x+y=-2+3=1 ≠ 3 so YES now check the other solution 7-6=-1 OK
Now check the non-linear condition for F:
S1: (-2,3)
y-15=3-15=-12
-x^2+4x=-(-2)^2+4*(-2)=-12 good
S2:(7,-6)
y-15=-6-15=-21
-x^2+4x=-(7^2)+4(7)=-49+28=-21 also good,
So Solution set (1) matches tile F
(2) Given solutions {(-5,8),(3,0)}
We proceed in a similar way, to find that
-5+8=3 & 3+0=3 (matches A) and nothing else.
Check non-linear conditions (optionally, I transposed the terms to make comparison easier)
A. x^2+x-y=(-5)^2+(-5)-8=25-5-8=12 (looks good)
x^2+x-y=(3)^2+(3)-0=9+3=12 (looks even better)
So we determined that {(-5,8),(3,0)} is the solution for tile A.
(3) For solution set {(-2,5),(3,-5)}
Check linear conditions:
x+y=3 and -3, so does not satisfy A,& F.
x-y=-7 and 8, so does not satisfy B
2x+y=5 and 1 so satisfies C
x+2y=8 & -7 so does not satisfy D
-x+y=7 & -8 so does not satisfy E
Thus C is our only set. NOTE: if two distinct points satisfy one linear condition (say C), then both points cannot satisfy another non-equivalent linear condition, i.e. we didn't really have to check points D & E (which are not equivalent linear conditions as C) once we have found C.
Now check non-linear conditions:
x^2-3x-y=(-2)^2-3(-2)-5=5 ok
x^2-3x-y=(3)^2-3(3)-(-5)=5 ok
So solution set (3) matches tile C.
@officiallyqueenz, for your benefit, I will leave one for you as exercise. Please proceed to find the system for solution set (4). Post a your work as comments if you get stuck, or your answer for verification if you wish.
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