Help i,m suck and i cant find the answer

Simplify 8/-3 ÷ -4/9 A. -8 B. -6 C. 6 D. 8

geniusboy [140]

Answer:

C. 6

Step-by-step explanation:

to divide by a fraction multiply by the recirpocal of that fraction.

8/3 ÷ 9/4

reduce the numbers with GCF 4 which equals 2/3 x 9

reduce the numbers with GCF 3 which equals 2x3= 6

4 0

3 years ago

louise bought 80 metres of fencing to make an enclosure for her pet dog .tommy if louise expects a rectangular enclosure what is

OleMash [197]

Answer:

400 m^2.

Step-by-step explanation:

The largest area is obtained where the enclosure is a square.

I think that's the right answer because a square is a special form of a rectangle.

So the square would be 20 * 20 = 400 m^2.

Proof:

Let the sides of the rectangle be x and y m long

The area A = xy.

Also the perimeter 2x + 2y = 80

x + y = 40

y = 40 - x.

So substituting for y in A = xy:-

A = x(40 - x)

A = 40x - x^2

For maximum value of A we find the derivative and equate it to 0:

derivative A' = 40 - 2x = 0

2x = 40

x = 20.

So y = 40 - x

= 40 - 20

=20

x and y are the same value so x = y.

Therefore for maximum area the rectangle is a square.

3 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: