The length of A"B" is 20 units
<h3>How to determine the length of A'B'?</h3>
From the figure, we have:
A = (1, 4)
B = (4, 8)
The distance AB is:

So, we have:

Evaluate

This gives
AB = 5
The scale factor of dilation is 4.
So, we have:
A'B' = 5 * 4
Evaluate
A'B' = 20
Hence, the length of A"B" is 20 units
Read more about dilation at:
brainly.com/question/18977334
#SPJ1
Answer:
second one
Step-by-step explanation:
f(3)=g(3)=6
Answer:
3
Step-by-step explanation:
9= 3*3
42=3*7*2
let us take any two points here (5,20) and (7,30)
now let us use slope formula to get its slope


slope =5
now let us use one coordinate (say (5,20)) and slope to get the y intercept
20= 5*5 +b
b=-5
plugging the values of b and m in the given equation we get
y=5x-5
or c=5m-5
Answer:
2/14, 4/28, 5/35, 7/70 or just 2/14
Step-by-step explanation:
Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14
And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.