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Alexus [3.1K]
4 years ago
11

How can we show 10 minus 6?

Mathematics
1 answer:
neonofarm [45]4 years ago
8 0
10-6=4
You cannot use 6-10 because that would give you a negative answer.
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What is the mean of the data set?
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Answer:

The answer is 26. Add them all together then divide by the amount of numbers.

Step-by-step explanation:

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3 years ago
If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =
Nookie1986 [14]
You simply multiply the two and distribute to solve. I am starting with t(x) because I think it is easier.

(x+4)*(2x^2+3x-4) 
2x^3+3x^2-4x+8x^2+12x-16 (distribute)
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What is the solution to the equation g(x)=3?
aksik [14]

Answer:

  3 ≤ x < 5

Step-by-step explanation:

The top horizontal line segment on the graph corresponds to g(x) = 3. That segment extends over the interval from 3 to 5, including 3, but not including 5. So ...

  g(x) = 3 for 3 ≤ x < 5 . . . . matches the last choice

3 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
2 years ago
A. True/False
ra1l [238]

Answer:

True

Step-by-step explanation:

x^{2} -6x=9

subtract 9 from both sides

x^{2} -6x-9

<em>plz mark me brainliest.</em> ;)

5 0
3 years ago
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