Answer:
x + 6
Step-by-step explanation:
Edit:
A moderator mentioned my answer had a mistake: turned out the question posted was incomplete. The complete question should read:
"
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
x – 6
x – 3
x + 1
x + 6
"
As shown in the same graph, f(x) cross the x-axis at x = -6, -3 and 0.
When a polynomial crosses the x-axis at x = a, (x - a) must be a factor.
So (x + 6), (x + 3) and x are factors of f(x).
Of the options, the correct answer is x + 6.
The complete question with verified answer is here: brainly.com/question/3875529
I would say that it's an acute angle ....
Answer:
Area = πr², where "r" is some distance "y" and/or the function "(1/6)x"; depending on the situation
Step-by-step explanation:
If I'm picturing this correctly, you'll have conical shape after revolving the function about the x-axis. If you took some generic slice and wanted to find the area of the resulting cross-section, then you would have a circle whose radius is some arbitrary value of the line that matches the slice.
For example:
y = (1/6)x right?
If you took a slice at x = 2, then the radius of the resulting cross-sectional circle would be equal to y = (1/6)•2 =1/3.
From here you just plug it into the area of a circle, πr², to get an area of π/3.
Except with an integral you need to take all the points on the interval, so the radius comes out to be the function itself.
Assuming your integral is in terms of dx, r=y. But in order to integrate in terms of dx you must replace "y" with its function (1/6)x. So ultimately r=(1/6)x and Area = π(1/6)x.
For 9 x=2 and a=1
the other two I'm not sure about but i know the first one because 2x=22so 2x2
=4 and 4x=41so4x1=4 and4+4=8
